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Dmitry_Shevchenko [17]
2 years ago
9

PLS HELP ASAP FIRST CORRECT ANSWER GETS BRAINLEIST​

Mathematics
2 answers:
Sergio039 [100]2 years ago
4 0

Answer: 9 cm

You can figure this out because the unknown side combined with the 5cm side is equal to the 14cm side. Therefore, subtract 5 from 14 to find out the unknown side.

nikitadnepr [17]2 years ago
4 0
The missing side is 9cm

The perimeter is 44cm

Explanation:

To find the missing side you subtract 5 from 14 since the missing side added to 5 would have the length of 14.
So, 14-5 = 9

The perimeter is calculated by adding all sides:
14 +8+5+3+9+5= 44
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Reptile [31]

Answer:

5

Step-by-step explanation:

the order of the surd is 5

5 0
3 years ago
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Write the set of points greater than or equal to −5−5 but strictly less than 44, excluding 00, as a union of two intervals (if y
Alecsey [184]
What we want to draw is the half closed interval:

                                          I=   [-5, 4) excluding 0,

as the union of 2 different intervals say a and b.

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Then the smallest value of a is -5, and the largest possible value of a is 0, not included, if we want to write a as an interval, without "gaps", or "holes".

So a=[-5, 0)

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Answer: [-5, 4)=[-5, 0)∪(0, 4)

7 0
3 years ago
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

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5 0
3 years ago
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Step-by-step explanation:

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w=20

P=l+w+l+w

120=5x-10+2x+5x-10+2x

120= 14x-20

120+20=14

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