Answer:
3/2
Step-by-step explanation:
when you plot it time is x and distance is y so go up 3 right 2
Answer:
answer is down below
Step-by-step explanation:
9 to 16
<h3>
The probability of selecting a random student who is enrolled in both the courses is 0.280.</h3>
Step-by-step explanation:
Here, the total number of freshman in the university = 500
The number of students enrolled in Economics = n(E) = 323
The number of students enrolled in Mathematics = n(M) = 205
The number of students enrolled in Both Economics and math
= n(E∩M ) = 140
Let F : Event of selecting a student who is enrolled in both the courses
So, from the given data:
So, the probability of selecting a random students who is enrolled in both the courses is 
For clearly look we can seperate the number parts and the letter parts because they are all “*” and “/“ caculation
Initial fraction: (20 * a^2 * b) / ( 5 * a * b^2) = (20 / 5) * (a^2 / a) * (b / b^2)
Result: (4*a) / (b) = (4*a) / (1*b) = (4/1) * (a/b)
As you can see the result is a fully simplifying form so just simplify any thing you can from initial fraction
20/5 = 4/1 (both nume and deno are divided by 5)
a^2 / a = a/1 (divided by a)
b / b^2 = 1/b (divided by b)
Multiply all above we get the result 4a/b (just for checking whether we did right or not)
Next, multiply all that we have divided in previous step: 5*a*b = 5ab
=> problem solved
