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2 years ago

Find the median of the data. 12, 33, 18, 28, 29, 12, 17, 4, 2 The median is

Mathematics

2 answers:

Nookie1986 [14]2 years ago

8 0

The median is 17

You have to put the numbers in order to least to greatest then find the number in the middle

Reptile [31]2 years ago

3 0

Answer:

The median is 29

Step-by-step explanation:

So you have to cross out 12 then 2 then 33 then 4 then 18 then 17 then 28 then 12 and the last number that's standing is 29.

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Exercises Part 2 Calculator by justifying the measurement of angles: CAD and CDA &lt

Diano4ka-milaya [45]

Answer:

yea

Step-by-step explanation:

3 0

2 years ago

(x1,y1) is (-4,-2) and (x2,y2) is (2,4)

olga nikolaevna [1]

Answer:

y = x+2

Step-by-step explanation:

(x1,y1) is (-4,-2) and (x2,y2) is (2,4)

Slope intercept form is y = mx+b

m = slope

b = add on

Slope = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute numbers

Slope = $\frac{4-(-2)}{2-(-4)}$

Two negatives = one positive

Simplify

$Slope = \frac{4+2}{2+4}=\frac{6}{6}=1$

The slope is 1

We can substitute y, x, and the slope

4 = 2*1 + b

4 = 2+b

b = 2

Slope intercept form is y = mx+b

Answer is y = x+2

Hope this helps :)

6 0

2 years ago

10+3c≤1 ????????????????????????

stiks02 [169]

Answer:

c<-3

Step-by-step explanation:

move the constant to the right-hand side and change its sing

Then canculate the difference

Then divide both sides for the inequality of 3

6 0

2 years ago

Describe the expression (4x÷2)-9y

sertanlavr [38]

(4x ÷ 2) - 9y is difference of two terms.

4 0

2 years ago

The savings account offering which of these APRs and compounding periods offers the best APY?

zzz [600]

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\
$

$\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\
$

$\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1$

7 0

2 years ago

Read 2 more answers