Factor 6x^2-11x-35
6x^2-11x-35
= (3x+5)(2x-7)
Answer: (3x+5)(2x-7)

Explanation
any vector in the plane can be writen as a linear combination of the 2 standar unit vectors

hence
Step 1
component form

now, as a linear combination

I hope this helps you
19539 bacteria will be present after 18 hours
<u>Solution:</u>
Initial value of bacteria N = 6000
Value after 4 hours
= 7800
<em><u>The standard exponential equation is given as:</u></em>

where
N is amount after time t
No is the initial amount
k is the constant rate of growth
t is time
Plugging in the values in formula we get,

Solving for "k" we get,

Taking "ln" on both sides, we get


On solving for ln, we get k = -0.0656
The equation becomes, 
Now put "t" = 18,

Hence the bacteria present after 18 hours is 19539
Answer:
S' (1,-2)
S'' (0,0)
Step-by-step explanation:
Yes, yes it is :)
your welcome