Question

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, negative 7) and (0, 2). Everything to the left of the line is shaded.
Which linear inequality is represented by the graph?

y < 3x + 2
y > 3x + 2
y < One-thirdx + 2
y > One-thirdx + 2

Answer 1

The inequality described can be written as:

y < 3x + 2.

How to get the inequality?

First, we know that we have a dashed line, and the region to the left of that line is shaded, then we will have:

y < line.

The linear equation is of the form:

y = a*x + b

Where a is the slope and b is the y-intercept.

Remember that if a line passes through the points (x₁, y₁) and (x₂, y₂), then the slope is:

$a = \frac{y_2 - y_1}{x_2 - x_1}$

Here we know that the line passes through (-3, -7) and (0, 2), so the slope is:

$a = \frac{2 - (-7)}{0 - (-3)} = 9/3 = 3$

And because the line passes through (0, 2), the y-intercept is 2, then the inequality is:

y < 3x + 2.

If you want to learn more about inequalities:

brainly.com/question/2516147

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