Find the center, (H,K) (x+3)^2+(y+1)^2=9
1 answer:
The center of the equation of the circle will be (h, k) = ( -3. -1).
<h3>What are a circle and its equation?</h3>A circle can be characterized by its center's location and its radius's length.
Let the center of the considered circle be at (h,k) coordinate.
Let the radius of the circle be 'r' units.
Then, the equation of that circle would be:
We have been given an equation of the circle as
By comparing the equation with general equation of the circle
we get,
h = -3
k = -1
r = 3
So, the center of the equation will be (h, k) = ( -3. -1).
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Answer:
Option D. 8 units
Step-by-step explanation:
step 1
Find the area of rectangle
The area of rectangle is
step 2
Find the length side of the square with the same area of rectangle
The area of a square is
where
b is the length side of the square
we have
substitute
take the square root both sides
therefore
The length side of the square is 8 units
Answer:
Step-by-step explanation:
Part A
x-intercepts of the graph → x = 0, 6
Maximum value of the graph → f(x) = 120
Part B
Increasing in the interval → 0 ≤ x ≤ 3
Decreasing in the interval → 3 < x ≤ 6
As the price of goods increase in the interval [0, 3], profit increases.
But in the price interval of (3, 6] profit of the company decreases.
Part C
Average rate of change of a function 'f' in the interval of x = a and x = b is given by,
Average rate of change =
Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,
Average rate of change =
=
= 30