Answer:
Not sure but the answer to 14(3/2 x 1/4) is 5.25
Step-by-step explanation:
9,090,900.0099 is the answer.
Answer:
a) The mean is ![\mu = 60](https://tex.z-dn.net/?f=%5Cmu%20%3D%2060)
b) The standard deviation is ![\sigma = 9](https://tex.z-dn.net/?f=%5Csigma%20%3D%209)
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.
This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when ![X = 55.5, Z = -0.5](https://tex.z-dn.net/?f=X%20%3D%2055.5%2C%20Z%20%3D%20-0.5)
So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![-0.5 = \frac{55.5 - \mu}{\sigma}](https://tex.z-dn.net/?f=-0.5%20%3D%20%5Cfrac%7B55.5%20-%20%5Cmu%7D%7B%5Csigma%7D)
![-0.5\sigma = 55.5 - \mu](https://tex.z-dn.net/?f=-0.5%5Csigma%20%3D%2055.5%20-%20%5Cmu)
![\mu = 55.5 + 0.5\sigma](https://tex.z-dn.net/?f=%5Cmu%20%3D%2055.5%20%2B%200.5%5Csigma)
The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.
This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when ![X = 71.52, Z = 1.28](https://tex.z-dn.net/?f=X%20%3D%2071.52%2C%20Z%20%3D%201.28)
So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![1.28 = \frac{71.52 - \mu}{\sigma}](https://tex.z-dn.net/?f=1.28%20%3D%20%5Cfrac%7B71.52%20-%20%5Cmu%7D%7B%5Csigma%7D)
![1.28\sigma = 71.52 - \mu](https://tex.z-dn.net/?f=1.28%5Csigma%20%3D%2071.52%20-%20%5Cmu)
![\mu = 71.52 - 1.28\sigma](https://tex.z-dn.net/?f=%5Cmu%20%3D%2071.52%20-%201.28%5Csigma)
Since we also have that ![\mu = 55.5 + 0.5\sigma](https://tex.z-dn.net/?f=%5Cmu%20%3D%2055.5%20%2B%200.5%5Csigma)
![55.5 + 0.5\sigma = 71.52 - 1.28\sigma](https://tex.z-dn.net/?f=55.5%20%2B%200.5%5Csigma%20%3D%2071.52%20-%201.28%5Csigma)
![1.78\sigma = 71.52 - 55.5](https://tex.z-dn.net/?f=1.78%5Csigma%20%3D%2071.52%20-%2055.5)
![\sigma = \frac{(71.52 - 55.5)}{1.78}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7B%2871.52%20-%2055.5%29%7D%7B1.78%7D)
![\sigma = 9](https://tex.z-dn.net/?f=%5Csigma%20%3D%209)
![\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60](https://tex.z-dn.net/?f=%5Cmu%20%3D%2055.5%20%2B%200.5%5Csigma%20%3D%2055.5%20%2B%200.5%2A9%20%3D%2055.5%20%2B%204.5%20%3D%2060)
Question
The mean is ![\mu = 60](https://tex.z-dn.net/?f=%5Cmu%20%3D%2060)
The standard deviation is ![\sigma = 9](https://tex.z-dn.net/?f=%5Csigma%20%3D%209)
10.5 ( near parallel to the one next to x which will equal 11 or 11.5 but 10.5 is associated with its compression.
Answer = 10.5
(thanks if you give branliest it is always appreciated)
Answer:
p> -4
Step-by-step explanation:
3p + 2 > -10
3p > -10 -2
p> -4