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2 years ago

PLEASE HELP MEEE :))

Mathematics

2 answers:

Anton [14]2 years ago

6 0

Answer:

1.) 5

3²=9

9+1=10

10/2=5

2) 12

5×2=10

10-10=0

4×3=12

0+12=12

4) 69

3×2=6

6×3=18

18-5=13

13+10=23

23×3=69

I hope this helps:

ivanzaharov [21]2 years ago

5 0

Answer:

Question (1) is 5

Step-by-step explanation:

3x3=9

9+1=10

— = 5

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8090 [49]

Answer:

James bought 11 good tickets and 5 bad tickets.

Step-by-step explanation:

Given that:

Cost of each good ticket = $8

Cost of each bad ticket = $5

Total amount spent = $113

Total tickets bought = 16

Let,

x be the number of good tickets bought

y be the number of bad tickets bought

x+y=16 Eqn 1

8x+5y=113 Eqn 2

Multiplying Eqn 1 by 5

5(x+y=16)

5x+5y=80 Eqn 3

Subtracting Eqn 3 from Eqn 2

(8x+5y)-(5x+5y)=113-80

8x+5y-5x-5y=33

3x=33

Dividing both sides by 3

$\frac{3x}{3}=\frac{33}{3}\\x=11$

Putting x=11 in Eqn 1

11+y=16

y=16-11

y=5

Hence,

James bought 11 good tickets and 5 bad tickets.

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2 years ago

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3 years ago

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Ilia_Sergeevich [38]

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Step-by-step explanation:

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Vera_Pavlovna [14]

Multiply numerator and denominator by the conjugate of the denominator

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Conjugate of the denominator: -10 - 8i

Operation:

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2 years ago