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OLga [1]
2 years ago
15

a cylinder has a height of 6 meters and a diameter that is 6 times the measure of the height. using 3.14 or pi which of the foll

owing can be used to calculate the volume of the cylinder
Mathematics
1 answer:
Andrew [12]2 years ago
8 0

The volume of the cylinder with height 6 meters and the radius 18 meters is 6,104.16 m^{3}.

<h3>What is a volume of a cylinder?</h3>

The volume of a cylinder is the capacity of the cylinder which calculates the amount of material quantity it can hold.

Given that, the height of a cylinder=6 meters and the diameter of a cylinder=6×6=36 meters (A diameter that is 6 times the measure of the height)

Now, radius (r)=\frac{d}{2} =18 meters

\pi =3.14

We know that, the volume of the cylinder=\pi r^{2} h

=3.14\times 18^{2} \times 6 m^{3}

=6,104.16 m^{3}

Hence, the volume of the cylinder with height 6 meters and the radius 18 meters is 6,104.16 m^{3}.

To learn more about the volume of the cylinder visit:

brainly.com/question/16134180

#SPJ1

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Answer:

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Step-by-step explanation:

According to question ,

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The Force experience on the spring is calculated from the Hook's Law

<u>The principal state that , the force applied on spring to extend or compress the spring to some distance is proportion to that distance. </u>

Let the force be F

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where K is spring constant and X is its displacement

Negative sign shows displacement of spring once it is stretched

And K is spring constant

So ,Force = ( - ) 7 × 0.3

I.e Force  =  - 2.1 Newton       Answer

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3 years ago
What is the value of y in the equation 4 + y = −3?
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An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

\dfrac{dC}{dw}= 0  \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}

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height = ( 88})^{1/3} (3)^{1/3} \ feet

6 0
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