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Mademuasel [1]
2 years ago
13

Which Of the following pairs of functions are inverse of each other?

Mathematics
1 answer:
damaskus [11]2 years ago
5 0

One way is to solve for the inverse of the first function

remember, to solve, replace f(x) or g(x) with y, switch x and y, solve for y and replace it with f^{-1} (x)

A.

f(x)=x/2+8\\y=x/2+8\\x=y/2+8\\x-8=y/2

2x-16=y

f^{-1}=2x-16

nope, not A

<h3>What is the inverse function?</h3>

The inverse function of a function f is a function that undoes the operation of f. The inverse of f exists if and only if f is bijective, and if it exists, is denoted by {\displaystyle f^{-1}.}

B.

f(x)=3x^3+16\\y=3x^3+16x=3y^3+16\\x-16=3y^3\\(x-16)/3=y^3

f^{-1}(x)=\sqrt[3]{((x-16)/3)}

nope, not the same

not B

C.

f(x)=18/x-9\\y=18/x-9\\x=18/y-9\\x+9=18/y\\y(x+9)=18\\y=18/(x+9)\\f^{-1}(x)=18/(x+9)

The correct, answer is C.

To learn more about the inverse function visit:

brainly.com/question/2972832

#SPJ1

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Solve for y:<br> y+5x=6;x= -1,0,1
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When x = -1

y + 5x = 6

y = 6 - 5x

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What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?
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Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

AB = \sqrt{(11-4)^{2}+(3-3)^{2}}

AB = \sqrt{(7)^{2}+(0)^{2}}

AB = \sqrt{49}

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As take B(11, 3) to C (11, 9).

BC = \sqrt{(11-11)^{2}+(9-3)^{2}}

BC = \sqrt{(0)^{2}+(6)^{2}}

BC = \sqrt{36}

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BC = 6 units

As take C (11, 9) toD (4, 9).

CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}

CD = \sqrt{(7)^{2}+(0)^{2}}

CD = \sqrt{49}

\sqrt{49} =7

CD =  7 units

As take  D (4, 9) to  A (4, 3)

DA = \sqrt{(4-4)^{2}+(3-9)^{2}}

DA = \sqrt{(0)^{2}+(-6)^{2}}

DA = \sqrt{36}

\sqrt{36} =6

DA =  6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value  in the above

Area of rectangle =  7 × 6  

                             = 42 units ²

Therefore the area of a rectangle is 42 units ².

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