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2 years ago

Solve each of the equations below and classify them based on their solution.

Mathematics

1 answer:

adell [148]2 years ago

5 0

Answer:

Answers are below

Step-by-step explanation:

1.) No solution

2.) Unique solution

3.) Unique solution

4.) No solution

I graphed the equation that had a unique solution on the graph below.

If these answers are correct, please make me Brainliest!

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Type the integer that makes the following addition sentence true:<br><br> -3 + = -11

konstantin123 [22]

An integer that would work is 14 so -3 + 14 = -11

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3 years ago

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Betty can mow a lawn in 20 minutes. Bullwinkle can mow the same lawn in 60 minutes. How long does it take for both Betty and Bul

inn [45]

Answer:

15 minutes

Step-by-step explanation:

Betty mows at 3 times the speed that Bullwinkle does, so is equivalent to having 3 Bullwinkles in her place. That makes the lawn get mowed as though 4 Bullwinkles were working, so it will take 1/4 the time it takes Bullwinkle to mow the whole yard. 1/4 of 60 minutes is 15 minutes.

Working together, Betty and Bullwinkle will take 15 minutes to mow the lawn.

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3 years ago

Find the tangent line equation of the curve at the given point. Y=arcsin(7x) at the point where x=sqrt2/14

Mumz [18]

Answer:

$Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})$

Step-by-step explanation:

The equation of the curve is

$Y = sin^{-1}(7x)$

To find the equation of tangent we need to differentiate this equation w.r.t x

So, differentiating we get

$Y'=\frac{7}{\sqrt{1-49x^2} }$

This would give the slope of the tangent line at any given point of which x coordinate is known. In the present case it is $x = \sqrt{\frac{1}{7} }$

Then slope would accordingly be

$Y'=\frac{7}{\sqrt{1-49/49} }$

= ∞

For, $x = \sqrt{\frac{1}{7} }$ , $Y = sin^{-1}(7/7)= \pi/2$

Equation of tangent line, in the point slope form, would be $Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})$

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2 years ago

How to do the problem

trapecia [35]

Step-by-step explanation:

$g(0.5) = 2 \\ \\ h(x) = g(x).f(x) \\ \therefore \: h(2) = g(2).f(2) \\ \therefore \: h(2) = 5 \times 2\\ \therefore \: h(2) = 10\\ \\ \\ j(x) = g(x) - f(x) \\ \therefore \: j(4) = g(4) - f(4) \\ \therefore \: j(4) = 9 - 8\\ \therefore \: j(4) = 1\\ \\ \\$

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2 years ago

2×6 <br>euruuryduruhdhdhd

Pachacha [2.7K]

2 x 6 = 12

Hope it helps :)

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3 years ago

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