Match the answer with the question

Mathematics

1 answer:

vlada-n [284]3 years ago

7 0

Answer:

18219

Step-by-step explanation:

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A mathematics Teacher brought 40 expensive calculator at 16400 each and a number of cheaper calculator costing tshs 5900 each. S

Novay_Z [31]

Answer:

Step-by-step explanation:

First, let's find how much she spent on the expensive calculators

40 times $16400= $656,000

Now, lets find how much money she had for the cheap calculators.

$774,000- $656,000=$118000

Now that we have her budget (money remaining) for the cheaper calculators, lets divide that by the price for each individual calculator.

$118000/$5900=20

If you like my answer, please mark me as a brainliest! (I am new to this community.)

4 0

3 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

Match the following items.

Margarita [4]

1. Commutative property of adfition

2. Multiplicative inverse

3. Associative property of addition

4. Distributive property

5. Additive identity

8 0

3 years ago

Read 2 more answers