Answer:
The other side = 13 feets long
Step-by-step explanation:
Given that :
Scale of drawing : 2 inches represents 5 feets
Area of rectangular room according to scale drawing = 24.96 in²
Length of one side of the room = 12 feets
Length of other side = x
Area of rectangle = Length * width
If :
2 inches = 5 feets
x = 12 feets
x = (12 *2) / 5
x = 4.8 inches
Hence,
For the scaled drawing :
4.8 * width = 24.96
Width = 24.96 / 4.8
Width = 5.2 inches
Converting to feets according to scale:
2 inches = 5 feets
5.2 inches = x feets
x = (5.2 * 5 ) / 2
x = 13 feets
Other side is 13 feets long
Answer:
because it never changes.
To answer the question above, evaluate the number of cookies each of them placed on a tray. The calculations are shown below,
Ronny C1 = 0.15 x 20 = 3
Celina C2 = 3
Jack C3 = 0.30 x 20 = 6
Michelle C4 = 20 - (3 + 3 + 6) = 8
From the calculation above, <em>Michelle</em> placed the most number of brownies on the tray.
HAT MATH ARE U IN
i got part of it but it lost me the
<span>differ part of land is 49,500 but it lost meh hope it helps gl</span>
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
