3 years ago

Jess had three more nickels than dimes for a total of $1.50 how many of each coin did he

Mathematics

1 answer:

oee [108]3 years ago

3 0

n = d + 3

5n + 10d = 150 cents

Substitute to solve for "d":

5(d+3)+10d = 150

15d + 15 = 150

15d = 135

d = 9 dimes

n = d+3 = 9+3 = 12 nickels

So 12 nickels!!

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