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solong [7]
2 years ago
12

Analyze the graph. Which inequality represents the graph?

Mathematics
1 answer:
pishuonlain [190]2 years ago
6 0

Answer:

gh of did t6ueerydfhtrdhu

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The measured dimensions of a rectangle are 7m by 4m to the nearest whole unit. Find the minimum and maximum possible areas of th
Monica [59]

Answer:

Maximum area = Minimum area = 28 m².

Step-by-step explanation:

The length and the width of the rectangle are measured to be 7 m and 4 m respectively to the nearest whole number.

We have to find the maximum and minimum possible areas of the rectangle.

The maximum or minimum area is calculated only when length or width or both can vary and then only for a certain value of length and width the area becomes maximum or minimum.  

So, the maximum and minimum area of the rectangle will be the same i.e. (7 × 4) = 28 m². (Answer)

3 0
3 years ago
Like terms are two or more
Vanyuwa [196]
1. terms
2. variables
3. powers
7 0
3 years ago
What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)
matrenka [14]

Answer: QS=11.8cm


Step-by-step explanation:

1. You have the following information:

- The lenght of RS is 2 centimeters.

- The angle m∠S=80°.

- Cos80°=0.17

2. Therefore, you can calculate the lenght of the segment QS as following:

cos80=\frac{adjacent}{hypotenuse}

adjacent=2cm\\hypotenuse=QS\\cos80=0.17

3. Substitute values and solve for QS:

0.17=\frac{2cm}{QS}\\QS=\frac{2cm}{0.17} \\QS=11.76cm

4. To the nearest tenth:

QS=11.8cm

6 0
4 years ago
Rewrite the expression without the negative exponent.<br><br> 1/x^−8<br> (this is a fraction)
ser-zykov [4K]

Answer:

I believe the answer is x^8

Step-by-step explanation:

move x^-8 to the numerator in 1/x^-8 using the negative exponent rule 1/b-n = b^n.

8 0
4 years ago
A snail is at the bottom of a well. In the first 10 minutes, the snail climbs 23 7/12 inches. In the next 10 minutes, it clims 1
Alekssandra [29.7K]
I believe that the snail would be 43 5/12 inches away from the bottom after 20 minutes.
4 0
4 years ago
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