I think its "Yes it can because -3.5 lies to the left of -1.5"
Correct Ans:Option A. 0.0100
Solution:We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.
First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

So, 90 converted to z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.
Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
8/ Sine 50 = n/ Sine 90
8 sine 90 = n Sine 50
8 sine 90 / sine 50 = n
n = 10.4
Answer:
391
Step-by-step explanation:
First you must make the fraction a decimal so you can use it in an equation.
To do so move the . over to the left twice.
.68
Now multiply 575 by .68
575 x .68=391
Answer:
D
Step-by-step explanation:
C=2PI R
Radius is 24
pi is 3.14
Then you just solve it which turns out to be 150.8