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2 years ago

Determine Which equation is parallel to line BC and which is perpendicular to line BC

Mathematics

1 answer:

zhuklara [117]2 years ago

3 0

Answer:

Step-by-step explanation:

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1. 7+8-2 .

AnnZ [28]

Answer:

1. 13

2. 11

3. 10

4. 9

5. 12

6. 16

7. 14

8. 40

Step-by-step explanation:

8 0

3 years ago

Solving Quadratic Equations using the Square Root Property

Afina-wow [57]

Answer:

$x = -2$ or $x = -5$

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

$x^2 + 7x + 10 = 0$

Subtract 10 from both sides.

$x^2 + 7x = -10$

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

$x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = \dfrac{9}{4}$

Now we use the square root property, if

$x^2 = k$ , then

$x = \pm \sqrt{k}$

$x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}$

$x + \dfrac{7}{2} = \pm \dfrac{3}{2}$

$x + \dfrac{7}{2} = \dfrac{3}{2}$ or $x + \dfrac{7}{2} = -\dfrac{3}{2}$

$x = -\dfrac{4}{2}$ or $x = -\dfrac{10}{2}$

$x = -2$ or $x = -5$

5 0

3 years ago

Select the correct answer from each drop-down menu. Gino is buying wood screws at the corner hardware store. The table shows dif

patriot [66]

Without the table I will guess 5 is common to all 3 they are proportional

6 0

3 years ago

Danielle has her finals coming up and she's worried she'll fail her class. Her past 3 test grades were a 72. an 85, and a 68. Sh

natka813 [3]

Answer:

Step-by-step explanation:

7 0

3 years ago

Round 12.5478 to the nearest hundredths

solong [7]

Answer:

12.04

Step-by-step explanation:

Find the number in the hundredth place 4 and look one place to the right for the rounding digit 1 . Round up if this number is greater than or equal to 5 and round down if it is less than 5 .

6 0

3 years ago