Suppose a geometric sequence has a common ratio of 5. What is the next term after 9?
1 answer:
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9514 1404 393
Answer:
153 square units
Step-by-step explanation:
The figure is drawn in the attachment with some lengths and points labeled.
The figure can be considered to have an area that is the sum of the areas of rectangle ABFE and triangle FGH, with the area of triangle BCD subtracted.
That area is ...
A = area(ABFE) +area(FGH) -area(BCD)
= (15)(9) +(1/2)(9)(6) -(1/2)(6)(3)
= 135 +27 -9 = 153 . . . square units
