We know that a sample of 1800 computer chips revealed that 53% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature states that 54% of the chips do not fail in the first 1000 hours of their use.

We get that:

$n=1800\\\\p_1=53\%=0.53\\\\p_2=54\%=0.54\\$

We calculate the standar deviation:

$\sigma=\sqrt{\frac{0.53 \cdot (1-0.53)}{n}}=\sqrt{\frac{0.53 \cdot 0.47}{1800}}=0.01176$

We calculate the value of the test statistic:

$z=\frac{p_1-p_2}{\sigma}=\frac{0.53-0.54}{0.01176}=-0.85$

So the value of the test statistic is -0.85.

5 0

4 years ago

Write in slope-intercept form an equation of a line that passes through the point (8, 2) that is perpendicular to the graph of t

Citrus2011 [14]

Answer:

y= -1/4 x + 4

5 0

3 years ago

What is 5.48 million in scientific notation?

Amanda [17]

5,480,000 = 5.48 x 10^6

8 0

4 years ago

Read 2 more answers

Provide a real life algebra situation that has one solution (i.e. 3x = 6)

Sholpan [36]

3(x)=6
3(2)=6
which says 6=6

7 0

3 years ago