Answer:
Step-by-step explanation:
There aren't any choices, but I'd guess that she'd use pint or cup.
Answer:
x=(28-y)/3
Step-by-step explanation:
Just divide both sides by 3.
The quotient determined by two negative integers will be positive.
when both numbers are negative, it equals a positive. when one number is negative and the other is positive, it equals a negative.
hope this helps, God bless!
Answer:
false, false, true, true, true
Step-by-step explanation:
Let's check each of the answers by plugging them into the inequality.
-2 (false):
which is false.
-1 (false):
which is false.
0 (true):
which is true.
1 (true):
which is true.
2 (true):
which is true.
neverminding the jumbled lingo, is simply asking for the equation of the tangent line at that point, it says all tangents, well, there's only one passing there.
we can simply get the derivative of f(x) and take it from there.

since now we know the slope when x = 3/2, then we can just plug that into its point-slope intercept form, along with the coordinates.
