Answer:
espero y te sirva hay esta todo lo que necesitas
8/3 cups or 2 2/3
2/3 × 4/1 = 8/3
if u divide 3 into 8 it gives u 2 times with 2 places left
the 2 places equal 2/3
2 whole OR 6/3 + 2/3 = 8/3 OR 2 and 2/3
Answer:
64,9
Step-by-step explanation:
From my understanding the pattern would be:
Every other number is the next consecutive odd number,
( 1, 3, 5, 7 ) are all of the consecutive odds. (So the next odd is 9. )
That when we get to the part of where we get every other number for the remaining numbers, if you multiply the next even number by itself (square it).
4, 16, and 36 ( they are all perfect squares. )
They are the perfect squares of ( 2, 4, and 6) . So it makes sense that ( 8 ) is the next even number and you would square that and get ( 64 )
I hope this makes sense!!
The asymptote is the line the graph comes close to but never touches, so if you graph it out you should be able to see it! Sorry I couldn't help any more but good luck
ANSWER
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and
e have
EXPLANATION
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
Let us make y the subject and call it equation (2)


We put equation (2) in to equation (1)



Simplify to get,


Divide both sides by 31,



We put this value in to equation (2) to get,


We collect LCM to obtain,

