C. The light bulb will be off
This is due to the reason that the wire doesn’t go back to the battery :)
Answer:
1.89 seconds
Explanation:
t = Time taken
u = Initial velocity = 9.6 m/s
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
![v=u+at\\\Rightarrow 0=9.6-9.8\times t\\\Rightarrow \frac{-9.6}{-9.8}=t\\\Rightarrow t=0.97 \s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%200%3D9.6-9.8%5Ctimes%20t%5C%5C%5CRightarrow%20%5Cfrac%7B-9.6%7D%7B-9.8%7D%3Dt%5C%5C%5CRightarrow%20t%3D0.97%20%5Cs)
Time taken to reach maximum height is 0.97 seconds
![s=ut+\frac{1}{2}at^2\\\Rightarrow s=9.6\times 0.97+\frac{1}{2}\times -9.8\times 0.97^2\\\Rightarrow s=4.7\ m](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s%3D9.6%5Ctimes%200.97%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20-9.8%5Ctimes%200.97%5E2%5C%5C%5CRightarrow%20s%3D4.7%5C%20m)
So, the stone would travel 4.7 m up
So, total height ball would fall is 4.7+12.8 = 17.5 m
![s=ut+\frac{1}{2}at^2\\\Rightarrow 17.5=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{17.5\times 2}{9.8}}\\\Rightarrow t=1.89\ s](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%2017.5%3D0t%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.8%5Ctimes%20t%5E2%5C%5C%5CRightarrow%20t%3D%5Csqrt%7B%5Cfrac%7B17.5%5Ctimes%202%7D%7B9.8%7D%7D%5C%5C%5CRightarrow%20t%3D1.89%5C%20s)
Time taken by the stone to travel 17.5 m is 1.89 seconds
Answer: I'm not sure, but I think it would be a <em>total lunar eclipse </em>
Answer:
2081.65 m
Explanation:
We'll begin by calculating the time taken for the load to get to the target. This can be obtained as follow:
Height (h) = 3000 m
Acceleration due to gravity (g) = 10 m/s²
Time (t) =?
h = ½gt²
3000 = ½ × 10 × t²
3000 = 5 × t²
Divide both side by 5
t² = 3000 / 5
t² = 600
Take the square root of both side
t = √600
t = 24.49 s
Finally, we shall determine the distance from the target at which the load should be released. This can be obtained as follow:
Horizontal velocity (u) = 85 m/s
Time (t) = 24.49 s
Horizontal distance (s) =?
s = ut
s = 85 × 24.49
s = 2081.65 m
Thus, the load should be released from 2081.65 m.