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3 years ago

A hydrogen atom is in its ground state when its orbital electron:

Physics

1 answer:

Harlamova29_29 [7]3 years ago

8 0

It is in its ground state when its orbital electron is at its lowest energy amount.

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Identify one type of electromagnetic energy that has a shorter wave length than green light

11111nata11111 [884]

When you look at the acronym ROY G. BIV, you get the wavelengths from longest to shortest. Since Green is in the middle of ROY G. BIV, anything to the right of it would have a shorter wavelength. You can choose in the visible range Blue, Indigo, or Violet.

5 0

4 years ago

A horizontal force of 100 N is used to pull a crate, which weighs 500 N, at constant velocity across a horizontal floor. What is

Ilya [14]

Answer:

0.2

Explanation:

Horizontal force=100N

Weight of crate=500 N

We have to find the coefficient of kinetic friction.

Normal ,N=Weight=500N

Horizontal force, $F_x=\mu_kN$

Where $F_x$ =Horizontal force

N=Normal force

$\mu_k$ =Coefficient of kinetic friction

Substitute the values in the formula

$100=\mu_k(500)$

$\mu_k=\frac{100}{500}=0.2$

Hence, the coefficient of kinetic friction =0.2

8 0

3 years ago

A(n) __________ is a fast-flowing river of air at the boundary between the troposphere and stratosphere.

Ivahew [28]

<span>This is the jet stream. This air current flows from west to east along a typically-meandering path that is often used as a predictor of weather conditions. These currents are typically formed from the fact that the equator is warmer than the poles, and this allows the different-density air masses to develop an eastward-moving component.</span>

7 0

4 years ago

In measuring the width of a hair sample, a light of wavelength 500 nm is used. The hair sample is 40 um in radius. With the scre

sergejj [24]

Answer:

The distance of the second dark band away from the central bright spot be located is $5.625\times10^{-2}\ m$

Explanation:

Given that,

Wave length = 500 nm

Radius $d= 40\ \mu m$

Distance from the hair sample D= 6 m

We need to calculate the distance of the second dark band away from the central bright spot be located

$\sin\theta=\dfrac{y}{D}$

$\sin\theta=\dfrac{y}{6}$

Using formula for dark fringe

$(n-\dfrac{1}{2})\lambda=2d\sin\theta$

Put the value into the formula

$(2-\dfrac{1}{2})\times500\times10^{-9}=2\times40\times10^{-6}\times\dfrac{y}{6}$

$y=\dfrac{(2-\dfrac{1}{2})\times500\times10^{-9}\times6}{2\times40\times10^{-6}}$

$y=0.05625\ m$

$y=5.625\times10^{-2}\ m$

Hence, The distance of the second dark band away from the central bright spot be located is $5.625\times10^{-2}\ m$

6 0

3 years ago

Newton’s first law says that if motion changes, then a force is exerted. Describe a collision in terms of the forces exerted on

ira [324]

Answer:

In collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.

Explanation:

In a collision two objects, there is a force exerted on both objects that causes an acceleration of both objects. These forces that act on both objects are equal in magnitude and opposite in direction.

Thus, in collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.

4 0

3 years ago