All categories

2 years ago

A hydrogen atom is in its ground state when its orbital electron:

Physics

1 answer:

Harlamova29_29 [7]2 years ago

8 0

It is in its ground state when its orbital electron is at its lowest energy amount.

You might be interested in

Roughly speaking, the radius of an atom is about 10,000 times greater than that of its nucleus. If an atom were magnified so tha

skad [1K]

Answer:

0.124 miles

Explanation:

Since the radius of the atom R = 10000r where r = radius of nucleus. Now, if r = 2.0 cm = 0.02 m,

R = 10000r

= 10000 × 0.02 m

= 200 m

We know that 1 mile = 1609 m.

So the radius of the atom in miles is R = 200 m × 1 mile/ 1609 m = 0.124 miles

So, the radius of the atom in miles is 0.124 miles

4 0

3 years ago

How can a driver steer a car traveling at constant speed so that the magnitude of the acceleration remains constant. (Assume tha

ratelena [41]

<h2>Circular path i.e 1</h2>

Explanation:

If the driver steer into circular path , the acceleration of car will be

acceleration = velocity²/radius of circle

Because the velocity and radius of circle are both constant at all points . Thus the acceleration will also remain constant .

In case 3 and 4 , the radius of path changes . Because velocity is constant . Therefore the acceleration will not remain constant

3 0

2 years ago

A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the rail

disa [49]

Answer

given,

mass of ice hockey player = 110 Kg

initial speed of the skate = 3 m/s

final speed of the skate = 0 m/s

distance of the center of mass, m = 30 cm = 0.3 m

a) Change in kinetic energy

$\Delta KE = \dfrac{1}{2}mv_f^2 - \dfrac{1}{2}mv_i^2$

$\Delta KE = \dfrac{1}{2}m(0)^2 - \dfrac{1}{2}\times 110 \times 3^2$

$\Delta KE = - 495\ J$

b) Average force must he exerted on the railing

using work energy theorem

W = Δ KE

F .d = -495

F x 0.3 = -495

F = -1650 N

the average force exerted on the railing is equal to 1650 N.

7 0

2 years ago

Read 2 more answers

Two power lines run parallel for a distance of 220 m and are separated by a distance of 40.0 cm. If the current in each of the t

daser333 [38]

Answer:

The magnitude of force is 1.86 N and the direction of force is towards the other wire.

Explanation:

Given:

Current flowing through each power line, I = 130 A

Distance between the two power lines, d = 40 cm = 0.4 m

Length of power lines, L = 220 m

The force exerted by the power lines on each other is given by the relation:

$F = \frac{\mu_{0}LII }{2\pi d}$

Substitute the suitable values in the above equation.

$F = \frac{4\pi\times10^{-7}\times220\times130\times130 }{2\pi\times0.4}$

F = 1.86 N

Since the direction of current flowing through the power lines are opposite to each other, so the force is attractive in nature. Hence, the direction of force experienced by the power lines on each other is towards the each other.

5 0

2 years ago

Which nutrient is the most difficult to break down and, thus, is generally used last for energy in the body?

photoshop1234 [79]

Answer:

proteins

Explanation:

protiens is the most difficult nutrient to brek down

8 0

3 years ago

Read 2 more answers