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navik [9.2K]
3 years ago
10

List the types of electromagnetic radiation in order of decreasing energy per photon.

Physics
1 answer:
yulyashka [42]3 years ago
3 0

Incomplete question.The Complete question is here

List these types of electromagnetic radiation in order of (i) increasing frequency and (ii) decreasing energy per photon. a. gamma rays, b. radio waves, c. microwaves, d . visible light

Answer:

(i) (b) ,(c), (d), (a)

(ii) (a), (d), (c), (b)

Explanation:

For Part (i) increasing frequency

The frequency is directly proportional to energy.Therefore the order of increasing frequency is in the same direction as increasing energy

So the order is

(b) ,(c), (d), (a)

For Part (ii) decreasing energy per photon

This should be reverse direction from part (i)

(a), (d), (c), (b)  

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Observe the given figure and find the the gravitational force between m1 and m2.​
Leno4ka [110]

Answer:

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Explanation:

The details of the given masses having gravitational attractive force between them are;

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The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

F =G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

F = 6.67430 \times 10^{-11} \ N \cdot m^2/kg \times \dfrac{20 \ kg\times 50 \ kg}{(0.1 \ m+ 0.15 \ m)^{2}} \approx 1.06789 \times 10^{-6} \ N

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8 0
2 years ago
How would the self-inductance, l, of a coil change if you would increase its radius by a factor of two and increase its length b
pochemuha

The self-inductance of a coil will change by 8 times its original value by increasing its radius value by 2 and increasing the length of the coil by 2.

Self-Inductance: -

The definition of self-inductance is the induction of a voltage in a wire that carries current when the current in the wire is changing. In the instance of self-inductance, the circuit itself induces a voltage through the magnetic field produced by a changing current.

We know that the self-inductance of the coil is denoted by: -

L= µ *π*(r)^2*(N)^2*l

Where

L= Self-Inductance of the coil

µ= Magnetic Permeability Constant

r= Radius of the coil

l= Length of the coil

N= Number of turns of the coil

Here Self-inductance of the coil is directly proportional to the length of the coil and the square of the radius of the coil.

So,

On increasing the radius of the coil by a factor of 2 and the length of the coil by 2 the self-inductance of the coil increases by 8 times its original value.

Learn more about Self-Inductance here: -

" brainly.com/question/15293029 "

#SPJ4

3 0
2 years ago
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