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navik [9.2K]
3 years ago
10

List the types of electromagnetic radiation in order of decreasing energy per photon.

Physics
1 answer:
yulyashka [42]3 years ago
3 0

Incomplete question.The Complete question is here

List these types of electromagnetic radiation in order of (i) increasing frequency and (ii) decreasing energy per photon. a. gamma rays, b. radio waves, c. microwaves, d . visible light

Answer:

(i) (b) ,(c), (d), (a)

(ii) (a), (d), (c), (b)

Explanation:

For Part (i) increasing frequency

The frequency is directly proportional to energy.Therefore the order of increasing frequency is in the same direction as increasing energy

So the order is

(b) ,(c), (d), (a)

For Part (ii) decreasing energy per photon

This should be reverse direction from part (i)

(a), (d), (c), (b)  

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D. Speed !!!!!

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3 years ago
A guy wire 1034 feet long is attached to the top of a tower. When pulled taut, it touches level ground 699 feet from the base of
kolezko [41]

Answer:

80.386 degrees

Explanation:

We use the cosine equation here (which is the adjacent side of the unknown angle divided by the hypotenuse

The adjacent side = 699ft

The hypotenuse = 1034ft

using cos∅ = Adjacent/hypotenuse

where ∅ is the unknown angle

cos ∅ = 699/1034 = 0.167

∅ = arccos 0.167 = 80.368°

As easy as one can imagine

8 0
3 years ago
4. Name three things that all games, no matter where they are played around the world, have in common.
lilavasa [31]

Answer:

Key components of games are goals, rules, challenge, and interaction.

Explanation:

Hope I helped.

3 0
3 years ago
Read 2 more answers
QUESTION 4.
n200080 [17]

Answer:

Follows are the solution to this question:

Explanation:

Please find the correct question in the attachment file.

Let:

\overrightarrow{R}= R_i\hat{i}+R_j\hat{j}+R_k\hat{k}\\\\\overrightarrow{S}= S_i\hat{i}+S_j\hat{j}+S_k\hat{k}\\\\

Calculating the value of  \overrightarrow{R} \times \overrightarrow{S}:

\to \left | \begin{array}{ccc}\hat{i}&\hat{j}&\hat{K}\\R_i&R_j&R_k\\S_i&S_j&S_k\end{array}\right | = \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j]

Calculating the value of \overrightarrow{R}  \cdot (\overrightarrow{R} \times \overrightarrow{S}):

\to (R_i\hat{i}+R_j\hat{j}+R_k\hat{k}) \cdot ( \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j])

by solving this value it is equal to 0.

8 0
3 years ago
Please help with physics 2 part question giving 50 points
AveGali [126]

Answer:

2.88×10⁻⁹ s

2.40×10¹⁵ m/s²

Explanation:

Given:

v₀ = 12300 m/s

v = 6.92×10⁶ m/s

Δx = 0.997 cm = 0.00997 m

Part 1) Find: t

Δx = ½ (v + v₀)t

0.00997 m = ½ (6.92×10⁶ m/s + 12300 m/s) t

t = 2.88×10⁻⁹ s

Part 2) Find: a

(6.92×10⁶ m/s)² = (12300 m/s)² + 2a (0.00997 m)

a = 2.40×10¹⁵ m/s²

5 0
3 years ago
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