Answer:
v = 4t - t²/3
Explanation:
4 - k*6 = 0
k = 4/6 = 2/3
dv/dt = 4- 2/3 t
integral of dv = integral of (4-2/3 t) dt
v = 4t - t²/3
The Angle between horizontal and 1.25 plane
Answer:
24.4 m
Explanation:
sin 30 = 12.2 / x
x = 12.2 / sin 30 = 24.4 m
Answer:
Explanation:
Given the following :
Temperature (Th) of hot reservoir = 30°C (30 +273) = 303K
Temperature (Tc) of cold reservoir = 0°C (273K)
Quantity (Q) of heat transferred from hot reservoir = 400 J
Total change in entropy (ΔStotal) :
ΔStotal = ΔShot + ΔScold
ΔS = Q/T
Hot reservoir is losing 400J of heat ;
Q = - 400 J
ΔShot = Q/Th
ΔShot = - 400/303
ΔShot = - 1.32 J/K
ΔScold = Q/T
ΔScold = 400 / 273
ΔScold = 1.47 J/K
ΔStotal = ΔShot + ΔScold
ΔStotal = - 1.32 + 1.47
ΔS total = 0.15 J/K
Answer
Work done will be and it will be positive
Explanation:
We have given charge
We have to find work done in moving the charge from 15 volt to 8 volt
Let
So potential difference
We know that work done , here Q is charge and V is potential difference
So work done
It will be positive work done because work is done in moving charge from higher potential to lower potential