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olya-2409 [2.1K]
3 years ago
8

The sum of 3p and 6,cubed

Mathematics
2 answers:
muminat3 years ago
8 0

Answer:

Step-by-step explanation:

(3p+6)*3

=(3p)*3+6*3+3(3p)*2(6)+3(3p)(6)*2

=27(p*3)+216+162(p*2)+324p

=27(p*3)+162(p*2)+324p+216

egoroff_w [7]3 years ago
7 0

Answer:

Step-by-step explanation:

(3p+6)^3

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Add the x to both sides and it turns into Y = x + 4. If this isn't what you're looking for, please provide the answer choices.
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Create three new exponential equations to represent Alison, Cindy, and Javier. Alison loves social media and likes for her posts
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The new exponential equations to represent Alison, Cindy, and Javier would be 1/(1+e^-x) representing an s curve showing a lot of growth.

<h3>What is an exponential equation?</h3>

The exponential function is a mathematical function denoted by f(x)=\exp or e^{x}.

Here, he new exponential equations to represent Alison, Cindy, and Javier would be 1/(1+e^-x) representing an s curve showing a lot of growth while Cindy and Javier would be ln(x) and x^(1/2) as they will grow somewhat fast at first and then die out.

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Suppose SAT scores among college students are normally distributed with a mean of 500 and a standard deviation of 100. If a stud
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3 years ago
A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d
Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

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The unit vector of the force is

\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}

\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }

The net force acting on the object is

F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}

\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }

The net displacement will be

7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}

The work done will be F.d

w = f. d \\

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The work done on moving the object is 27ft*lbs

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Pleassse help! I will mark as brainliest :)
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I = 8.
k = 4
j = sqrt(8^2 + 4^2) = 8.944.
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3 years ago
Read 2 more answers
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