Answer:
h=94.87
Step-by-step explanation:
1. Volume of pyramid formula:
Base Edge * Height of Pyramid
2. We have variables:
V = 480, Base Edge = 10, Height of Base = 16 (Inch)
3. Plug into formula + Rearrange:
![\frac{3V}{h} =(b*h)^{2} [b^{2} *h^{2} ]](https://tex.z-dn.net/?f=%5Cfrac%7B3V%7D%7Bh%7D%20%3D%28b%2Ah%29%5E%7B2%7D%20%5Bb%5E%7B2%7D%20%2Ah%5E%7B2%7D%20%5D)
h≅94.868
Answer:
The side length of the large square is √2 times larger than the side length of the small square.
Step-by-step explanation:
Suppose we have a small square (square 1) and a large square (square 2). The area of the large square is twice that of the small square, that is,
A₂ = 2 A₁
A₂/A₁ = 2 [1]
The area of a square is equal to the length of the side (l) raised to the second power.
A = l²
l = √A
The ratio of l₂ to l₁ is:
l₂/l₁ = √A₂ / √A₁ = √(A₂/A₁)
We can replace [1] in the previous expression.
l₂/l₁ = √2
The side length of the large square is √2 times larger than the side length of the small square.
The distance between the abscissas (x-coordinates) of the points is equal to 13. That of the ordinates (y-coordinates) is equal to 10. Thus, the area is obtained by multiplying these values. The answer is equal to 130 units squared.
Cantaloup = 4v e 5c
graperfruit = 4v e 6c
tangerine = 4v e 5c
watermelon = 4v e 6c
4/5 = 0,8 = 8/10 = 4/5 = 4:5
cantaloup, graperfruit e tangerine
