Question

Will give brainliest plz hep!!!!!

Answer 1

Answer: The equation is of line "b"

Step-by-step explanation:

First we find the slope of the given line by using slope intercept form.

Converting the equation into slope intercept form

$5y=-2x+10$

Divide both side by 5 we get

$y= \frac{-2}{5} x+ 2$

On comparing with

$y =mx+c$

We get slope $m=\frac{-2}{5}$

as the slope of line is negative therefore the line will be either line "b" or line "d"

As line "b" pass from (0,2)

On putting point $x=0 &y=2$ in given equation we get

$2(0)+5(2)=0+10=10$

Which is equal to RHS of the line

Therefore the given equation is of line "b"

Now putting point (0,-2)

We get $2(0)+5(-2)=-10$

Which is not equal to RHS and therefore line "d" is not the required line

Therefore the given equation is of line "b"