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Sindrei [870]
2 years ago
11

Lucas is selling ribbons to raise money for the Juvenile Diabetes Research Foundation. His expenses include $23 for materials, p

lus $0.04 per ribbon. If Lucas charges $0.50 per ribbon, how many ribbons does he need to sell to break even? Write a system of equations that represents the situation. Let x represent the number of ribbons, and let y represent the expense or revenue. Solve the system of equations.
Mathematics
1 answer:
Tanzania [10]2 years ago
8 0

Using the equation, the amount of ribbon she needs to sell to break even is 50 ribbons.

<h3>How to represent system of equation and solve?</h3>

x = number of ribbons

y = expenses or revenue

Therefore, the system of equation for this situation is as follows;

y(expenses) = 23 + 0.04x

y = 23 + 0.04x

He charges $0.50 per ribbon. Therefore,

y(revenue) = 0.50x

y = 0.50x

Therefore, for her to break even,

23 + 0.04x = 0.50x

23 = 0.46x

x = 23 / 0.46

x = 50

Therefore, she needs to sell 50 ribbons for her to break even.

learn more equation here: brainly.com/question/20910741

#SPJ1

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Answer:  7\text{Ln}\left(e^{2x}+10\right)+C

This is the same as writing 7*Ln( e^(2x) + 10) + C

=======================================================

Explanation:

Start with the equation u = e^{2x}+10

Apply the derivative and multiply both sides by 7 like so

u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\

Integrating leads to

\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of \frac{14e^{2x}}{e^{2x}+10}

4 0
2 years ago
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6 0
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Andreyy89
D,

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A is correct because social studies has 4 students and reading has 8. Math has twice.
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