Question

Lucas is selling ribbons to raise money for the Juvenile Diabetes Research Foundation. His expenses include $23 for materials, plus $0.04 per ribbon. If Lucas charges $0.50 per ribbon, how many ribbons does he need to sell to break even? Write a system of equations that represents the situation. Let x represent the number of ribbons, and let y represent the expense or revenue. Solve the system of equations.

Answer 1

Using the equation, the amount of ribbon she needs to sell to break even is 50 ribbons.

How to represent system of equation and solve?

x = number of ribbons

y = expenses or revenue

Therefore, the system of equation for this situation is as follows;

y(expenses) = 23 + 0.04x

y = 23 + 0.04x

He charges $0.50 per ribbon. Therefore,

y(revenue) = 0.50x

y = 0.50x

Therefore, for her to break even,

23 + 0.04x = 0.50x

23 = 0.46x

x = 23 / 0.46

x = 50

Therefore, she needs to sell 50 ribbons for her to break even.

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