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Ket [755]
2 years ago
12

Helppppppppppppppppp pleaseeeeeeeeeeee​

Mathematics
1 answer:
alexandr1967 [171]2 years ago
4 0
Greater than 6 it’s labeled as 1 through 6 a fair dice has a probability of 16
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Stanley bought some tins and decided to fill them with brownies to give to his friends. Stanley baked 471 brownies. He put 9 bro
Temka [501]

3 brownies left over :) he filled 52 tins

8 0
3 years ago
Y = 15x + 10, where y is the total cost of renting 1 bicycle on the boardwalk for x hours. Determine whether the function is pro
vova2212 [387]

Answer:

The function is non-proportional.

Step-by-step explanation:

If the function was proportional, when the number of hours spent riding the bicycle is equal to 0, the total cost of renting the bicycle would also be 0. In other words, the function would be proportional if y=0 when x=0. However, this is not the case.

y=15x+10

Plug 0 into the equation as x

y=15(0)+10\\y=10

When 1 bicycle has been rented for 0 hours, the customer still has to pay 10 dollars just for renting it. When x=0, y=10. This means that the function is non-proportional.

I hope this helps!

4 0
3 years ago
HELP ILL GIVE YOU BRAINLIEST!
kirza4 [7]

Answer:

Factoring

Step-by-step explanation:

6x^2+13x-5=0\\6x^2-2x+15x-5=0\\2x(3x-1)+5(3x-1)=0\\(2x+5)(3x-1)=0\\x=-\frac{5}{2},x=\frac{1}{3}

3 0
2 years ago
What digit in the serial number of this dollar bill occurs most often? 6,8,5,8,2,8,5,8
Nastasia [14]
8 occurs most often.
7 0
3 years ago
In a​ study, 36​% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop
steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36​% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this​ area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly​ selected, 3 or fewer are in excellent health.

i.e. P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)

Formula :P(x=r)=^nC_r p^r q ^ {n-r}

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)

P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}

P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!}  (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}

P(x\leq 3)=0.390748

Hence  the probability that when 11 adults are randomly​ selected, 3 or fewer are in excellent health is 0.3907

5 0
3 years ago
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