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lianna [129]
2 years ago
5

Adrian works full time at the office supply store. He earns $525 each week. He wants to raise his income to at least $650 each w

eek, so he takes on a part-time job which pays $12 per hour. How many hours would Adrian need to work each week at his part-time job in order to raise his total weekly income to at least $650?
Mathematics
2 answers:
Sindrei [870]2 years ago
8 0
Answer: 10.4 hours to get his goal
slamgirl [31]2 years ago
4 0

Answer:The total number of hours worked in the week is 46. The hourly pay would be 40(14) + 6(21) = $686 per week. The annual earnings are 52(686) = $35,672. The salary pay is more than the hourly pay based on the typical hours worked each week given in the table. Therefore, the employee would probably want to choose the salaried pay.

Step-by-step explanation:

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Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
Find the value of X.
tatuchka [14]
This is the correct answer

4 0
1 year ago
HELP ASAP!!!!!!!! 15 POINTS + BRAINLIEST!!!!!!
Andre45 [30]
A) c=18
0.5c^2 +13=94
subtract 13 from both sides
0.5c^2 = 81
Square root of both sides to get c alone
0.5c=9
double c to make it just c
c=18

B) x=8
(x-2)^2+1=37
Subtract one from each side
(x-2)^2=36
square root each side
x-2=6
add the 2 over
x=8
6 0
2 years ago
PLEASE HELP, AND PLAESE EXPLAIN!!!
tankabanditka [31]

Answer:

D.   22.5 sq. un.

Step-by-step explanation:

W divides BU so that there is a ratio of 1;2 meaning that there are 3 parts.

That means that 3 parts is BUV; we know that one of those parts is 4.5 sq. un. so 4.5*3=13.5 sq. un.  - Also 4.5*2=9 to get WUV

V is the midpoint of the line BS so that means that BUV and UVS are equal

we know that BUV is 13.5 so we multiply that by 2 to get the whole triangle

=27

The last step is to get rid of BVW which we know is 4.5

27-4.5=22.5

7 0
2 years ago
Solve the system: 10x-9y=8 21y+15x=0.5
artcher [175]

Answer:

x = 1/2 y = -1/3

Step-by-step explanation:

Split it into 2 equations:

10x-9y=8

and

21y+15x=0.5

10x - 9y = 8

Step 1: Divide both sides by 10:

x = (8+9y)/(10)

Substitute x = (8+9y)/(10) into 21y+15x=0.5 :

21y + (3(8+9))/(2) = 0.5

Solve for y

<u>y= -1/3</u>

Substitute y= -1/3 into x = (8+9y)/(10)

<u>x = 1/2</u>

<u />

3 0
2 years ago
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