Answer:
Atomic mass of E is 128.24
Explanation:
- The percentage composition by mass of an element in a compound is given by dividing the mass of the element by the total mass of the compound and expressing it as a percentage.
- In this case; the compound Bi₂E₃
Percentage composition of bismuth = 52.07%
Percentage composition of E = 47.93%
Mass Bismuth in the compound is (2×208.9804) = 417.96 g
Therefore,
To calculate the atomic mass of E
52.07% = 417.96 g
47.93% = ?
= (47.93 × 417.96 ) ÷ 52.07 %
= 384.729
E₃ = 384.729
Therefore; E = 384.729 ÷ 3
= 128.24
The atomic mass of E is 128.24
Answer:
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Explanation:
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The homologous series ( not homogeneous series ) of n-propyl bromide is C3H7Br. It is also known as 1-Bromopropane
n-propyl bromide or 1-bromopropane, is a solvent that is used in cleaning metals, vapor degreasing and also for dry cleaning.
<h3>What is Homologous series?</h3>
Homologous series is a family of organic compound which follows a regular structural pattern and in which successive members differs from one another by a molecular formula of CH2
Below are some of their characteristics:
- The general formula of all compounds in the series is the same.
- They have the same functional group.
- Their physical properties such as melting point, boiling point, density, generally show a gradual change with increase of molecular formula in the series.
Learn more about homogeneous series:
brainly.com/question/14008526
Element 87 francium have the highest atomic size, so in short the closest element to francium have the high atomic size.