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Nuetrik [128]
3 years ago
5

Complete ionic equation for CuSO4 and Zn(NO3)2

Chemistry
2 answers:
UkoKoshka [18]3 years ago
8 0

Answer : The complete ionic equation in separated aqueous solution will be,

Cu^{2+}(aq)+SO_4^{2-}(aq)+Zn^{2+}(aq)+2NO_3^{-}(aq)\rightarrow Cu^{2+}(aq)+2NO_3^{-}(aq)+ZnSO_4(s)

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

CuSO_4(aq)+Zn(NO_3)_2(aq)\rightarrow Cu(NO_3)_2(aq)+ZnSO_4(s)

The complete ionic equation in separated aqueous solution will be,

Cu^{2+}(aq)+SO_4^{2-}(aq)+Zn^{2+}(aq)+2NO_3^{-}(aq)\rightarrow Cu^{2+}(aq)+2NO_3^{-}(aq)+ZnSO_4(s)

Assoli18 [71]3 years ago
7 0
It would (probably) be:
CuSO4 + Zn(NO3)2 -> Cu(NO3)2 + ZnSO4
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Answer:

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2) a. 0.4477 mol.

b. 0.4477 mol.

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Explanation:

1) Consider the following reaction:  iron (s) + chlorine (g) à iron (III) chloride

<em>a. Write the balanced chemical equation.</em>

  • The balanced equation should apply the law of conversation of mass that the no. of different atoms is equal in both sides of the reaction (reactants and products sides).

So, the balanced chemical equation is:

<em>2Fe(s) + 3Cl₂(g) → 2FeCl₃(s).</em>

It is clear that 2 mol of Fe(s) react with 3 mol of Cl₂(g) to produce 2 mol of FeCl₃(s).

<em>2) 25.0 g of iron reacts with excess chlorine gas.  </em>

<em>a. Calculate the moles of iron reactant.</em>

  • The no. of moles of Fe (n) can be calculated using the relation:

<em>n = mass/molar mass =</em> (25.0 g)/(55.845 g/mol) = <em>0.4477 mol.</em>

<em>b. Calculate the moles of iron (III) chloride.</em>

<em><u>Using cross multiplication:</u></em>

2 mol of Fe produce → 2 mol of FeCl₃, from stichiometry.

∴ 0.4477 mol of Fe produce → 0.4477 mol of FeCl₃.

∴ The no. of moles of iron (III) chloride produced is 0.4477 mol.

<em>c. Calculate the mass of iron (III) chloride.</em>

  • We can calculate the mass of iron (III) chloride produced using the relation:

mass of  iron (III) chloride = (no. of moles)*(molar mass) = (0.4477 mol)*(162.2 g/mol) = 72.61 g.

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Explanation:

The statement that is true of a chemical change among the statements given in the question is "It involves changes in the molecular structure". The correct option among all the options that are given in the question is the first option or option "A". I hope the answer has actually come to your help.

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