Answer:
Removing the worms is they first key to overcoming this problem. Thus you should ensure that the worms have not spread throughout the house/facility, or caused more damage.
Secondly, you should replace the pipes taht the worms got into, or clean them at most. If it’s simply worm droppings then just clean it, but if it’s more and worse than that alike slime then it is best to remove and replace it.
the only way the worms escaping could affect something is if they decontaminated it, or alas ate or destroyed it. Other than that if they died you could simply replace them, but e things cannot be replaced
Explanation:
You didn’t actually tell us any details so that the best I got from that
can I have brainlest pwease?
Answer:
188.5g of dextrose are needed
Explanation:
In Weight per volume percentage - %(w/v) -, the concentration is defined as the mass of solute in grams -In this case, dextrose-, in 100mL of solution.
As you want to prepare 725mL of a 26.0% (w/v) solution. you need:
725mL * (26g / 100mL) = 188.5g of solute =
<h3>188.5g of dextrose are needed</h3>
Answer:
Is there a picture To go with this?
Explanation:
Answer:
sorry i never learned this
Explanation:
Answer:
Option (A) the solid X is ground to a fine powder.
Explanation:
X(s) + 2B(aq) → X+(aq) + B2(g)
In the reaction above, the rate of the reaction will be highest, when X being a solid is ground to fine powder.
Grounding X to fine powder simply means increasing the surface area of X.
An increase in surface area of reactants will definitely increase the rate of reaction because the particles of the solid will collide with the right orientation and hence speed up the reaction rate.