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ad-work [718]
2 years ago
8

Forrest spills some acid on the lab floor. He notifies his teacher and begins to look for baking soda to neutralize the acid on

the floor.
Who should be notified next?
Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
5 0

The other students in the lab should be notified next in this type of scenario.

<h3>What is an acid?</h3>

This is a substance which donates protons and is very corrosive. It also turns blue litmus paper red.

When it was spilled and baking soda was used to neutralize it on the floor , it is best to inform the other students too so as to prevent them from being exposed by mistake thereby reducing risk of injury.

Read more about Acid here brainly.com/question/25148363

#SPJ1

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An object has a mass of 441 g and a volume of 10cm3
expeople1 [14]

Answer:

44.1g/cm3

Explanation:

d=m/v

=441/10

=44.1 g/cm3

3 0
3 years ago
Can y'all help me with number 4
astraxan [27]
I think the answer is A but i'm not sure
6 0
3 years ago
Read 2 more answers
3. Mercury is a liquid metal that has a density of 13.58 g/mL. Calculate the volume of mercury
Alona [7]

Answer:

0.03682 mL of mercury

Explanation:

We know the density of the mercury which is 13.58 g/mL

density = mass / volume

volume = mass / density

Now we can calculate the volume of 0.5 g of mercury:

volume = 0.5 / 13.58 = 0.03682 mL of mercury

5 0
3 years ago
What is generally the best approach when liquid from a large reagent bottle is needed in an experiment
Paul [167]

Answer:

See the answer below

Explanation:

The best approach would be to <u>pour the liquid from the large reagent bottle into a small-size beaker or reagent bottle first</u>, before measuring the required quantity out into the reaction vessel. This is necessary in order to maintain safety in the laboratory.

Pouring the liquid directly from the large reagent bottle into the measuring cylinder or directly into the reaction bottle can compromise safety in the laboratory. The liquid might splash out and cause harm to the handler or create other harmful circumstances in the laboratory.

6 0
3 years ago
Here are some data from a similar experiment, to determine the empirical formula of an oxide of tin. Calculate the empirical for
eduard

Answer:

Empirical formula of the Tin oxide sample is SnO₂

Explanation:

Tin reacts with combines with oxygen to form an oxide of tin.

Mass of crucible with cover = 19.66 g

Mass of crucible, cover, and tin sample = 22.29 g

Mass of crucible and cover and sample, after prolonged heating gives constant weight = 21.76 g

Mass of Tin oxide sample = 22.29 - 19.66 = 2.63 g

Mass of ordinary tin, after heating to breakdown the tin and oxygen = 21.76 - 19.66 = 2.1 g

Meaning that, mass of oxygen in the tin oxide sample = 2.63 - 2.1 = 0.53 g

Mass of Tin in the Tin Oxide sample = 2.1 g

Mass of Oxygen in the Tin oxide sample = 0.53 g

Convert these to number of moles

Number of moles of Tin on the Tin oxide sample = 2.1/118.71 = 0.0177

Number of moles of Oxygen in the Tin oxide sample = 0.53/16 = 0.0335

divide the number of moles by the lowest number

0.0177:0.0335

It becomes,

1:2

SnO₂

Hence, the empirical formula for the Tin oxide sample = SnO₂

7 0
3 years ago
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