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joja [24]
2 years ago
8

State the postulates of Dalton's atomic theory. ​

Chemistry
2 answers:
horrorfan [7]2 years ago
4 0
A theory of chemical combination, first stated by John Dalton in 1803. It involves the following postulates: (1) Elements consist of indivisible small particles (atoms). (2) All atoms of the same element are identical; different elements have different types of atom. (3) Atoms can neither be created nor destroyed.

(Brainliest me)
Lelechka [254]2 years ago
3 0

Answer:

<h3><u>The </u><u>Postulates of Dalton's Atomic Theor</u>y<u>:</u></h3>
  • All matter is made of very tiny particles called atoms.
  • Atoms are indivisible particles which cannot be created or destroyed in a chemical reaction.
  • Atoms of given element are identical in mass and chemical properties.
  • Atoms of different elements have different masses and chemical properties.
  • Atom combine in the ratio of small whole numbers to form compounds.
  • The relative number and kinds of atoms are constant in a given compound.

 

<u>-TheUnknownScientist 72</u>

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<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

To calculate the moles of a solute, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}

We are given:

Volume of sulfuric acid = 450mL = 0.45 L      (Conversion factor: 1 L = 1000 mL)

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Putting values in above equation, we get:

0.5mol/L=\frac{\text{Moles of sulfuric acid}}{0.45L}\\\\\text{Moles of sulfuric acid}=0.225mol

For the given chemical reaction:

H_2SO_4(aq.)+2NaHCO_3(aq.)\rightarrow Na_2SO_4(aq.)+2H_2O(l)+2CO_2(g)

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of sodium bicarbonate.

So, 0.225 moles of sulfuric acid will react with = \frac{2}{1}\times 0.225=0.45mol of sodium bicarbonate

To calculate the mass of sodium bicarbonate, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of sodium bicarbonate = 0.45 moles

Molar mass of sodium bicarbonate = 84.007 g/mol

Putting values in above equation, we get:

0.45mol=\frac{\text{Mass of sodium bicarbonate}}{84.007g/mol}\\\\\text{Mass of sodium bicarbonate}=38g

Hence, the correct answer is Option D.

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