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Dy/dx=2x+2
So velocity will be zero when 2x+2=0, x=-1
Since d2y/dx2=2, it has a constant positive acceleration of 2, so that when dy/dx=0 it is at an absolute minimum value for f(x), which is also the vertex.
y(-1)=1-2+3=2
So the vertex is at (-1,2), which is an absolute minimum so the parabola opens upwards.
And by symmetry we can say that f(0)=f(-2)=3 so you have another two points that you can see (-2,3) and (0,3)
1. I would call quadrants i, ii, iii, iv as a, b, c, d
<span>2.Which type of variables are usually on the y-axis and represent output?
</span>they usually are the dependent variables, that is, they depend on the x value, such as velocity, price, income.
3.Which type of variables are usually on the x-axis and represent input?
those are the independent variables such as time, distance, price.
<span>4.Which type of slope is represented on a graph as a horizontal line? </span>
the slope of an horizontal line is zero.
<span>5.Find the slope of 2x + 4y = 12
</span>the general form of the line is:
4y = - 2x + 12
y = -(1/2)x + 3
hence the slope is -1/2
You can do this on a calculator if you search up online radius and height measurement calculator.
