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3 years ago

Consider the table:

Mathematics

1 answer:

Tcecarenko [31]3 years ago

8 0

Answer:

1st 2nd and 3rd box

Step-by-step explanation:

1. It does not form a straight line because the output is not proportional. (it does not follow a pattern)

2. the line is not proportional because it does not follow a pattern or ratio of any kind (2468 is proportional because it follows the pattern of 2)

3. the origin is the coordinates (0,0) and the table has that labeled in the diagram therefore the graph does go through the origin

4. the output is not constant (output is 0149) because it does not show any sort of pattern. therefore the 4th box is incorrect.

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What is the slope of (-3,-2) and (-1,-5)

klio [65]

Answer:

-3/2

Step-by-step explanation:

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2 years ago

Read 2 more answers

1. During a field trip, 60 students are put into equal sized groups.

loris [4]

If you use for fingers and count bye five you should eventually reach 60 and how ever many fingers you have up is your answer. Witch =7

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2 years ago

Miguel has $49.13 in his bank account. He paid two fees of $32.50 each, and then he made two depositis of $74.25 each. What is t

mojhsa [17]

Answer:

$132.63

Step-by-step explanation:

$49.13 - ($32.50 × 2)

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3 years ago

Convert 0.5 lbs to grams

Luda [366]

Answer:

226.796

Step-by-step explanation:

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3 years ago

What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)

PIT_PIT [208]

9514 1404 393

Answer:

common denominator: (x² -4)
simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

a² -b² = (a -b)(a +b)

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

$\dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}$

3 0

2 years ago