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2 years ago

14

Solve for x ~

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ty! :)

2 answers:

mash [69]2 years ago

8 0

Answer:

Hey there !!!

14 x

Step-by-step explanation:

<em><u>Hope </u></em><em><u>it </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

Sonbull [250]2 years ago

5 0

$14x - 196 = 0 \\ \\ 14x = 196 \\ \\ x = \frac{196}{14} \\ \\ x = 14.$

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4 brainliest only correct answers

Gnoma [55]

Answer:

The point is in the fourth qaudrant

and, the point is 1 unit below the x-axis

Step-by-step explanation:

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4 0

3 years ago

babunello [35]

The selected statistical questions are as follows:

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4 0

3 years ago

What is the least value of x for which the inequality is true?<br> 16 > - 2x

Harrizon [31]

Answer:

Step-by-step explanation:

16>-2x

-2x<16

x>-8

6 0

3 years ago

olga nikolaevna [1]

The answer is linear pair postulate hope this helps.❤️

3 0

3 years ago

What is the sum of the geometric series

lbvjy [14]

If $S$ denotes the sum of the first $n$ terms of a geometric series with first term $a$ and common ratio $r$ , then

$S=a+ar+ar^2+\cdots+ar^{n-3}+ar^{n-2}+ar^{n-1}$
$rS=ar+ar^2+ar^3+\cdots+ar^{n-2}+ar^{n-1}+ar^n$
$\implies S-rS=a+(ar-ar)+(ar^2-ar^2)+\cdots+(ar^{n-1}-ar^{n-1})-ar^n$
$\implies (1-r)S=a(1-r^n)$
$\implies S=a=\dfrac{1-r^n}{1-r}$

Using summation notation, you have

$S=\displaystyle\sum_{x=1}^nar^{x-1}=\sum_{x=0}^{n-1}ar^x=a\dfrac{1-r^n}{1-r}$

In this case, you have $a=2$ , $r=\dfrac12$ , and $n=16$ . So the value of the sum is

$\displaystyle\sum_{x=0}^{15}2\left(\frac14\right)^x=2\dfrac{1-\left(\frac14\right)^{16}}{1-\frac14}\approx2.67$

Rounded to the nearest whole number, the answer would be 3.

4 0

4 years ago

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