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3 years ago

Is it possible for an exponential equation to have no solutions? If so, give an example. If not, explain why.

1 answer:

4 0

A function f(x) has solutions if we can find a value to plug in that leads to 0. In other words, there are solutions to f(x) = 0. Another term for "solution" is "root" or "x intercept"

An exponential function may cross the x axis at one point only. Though there are plenty of cases when there are no solutions at all. For instance, in the case of f(x) = (2^x) + 10

The right hand side will never be equal to zero no matter what you plug in for x. The graph will never cross the axis.

To answer your question, yes it is possible to have an exponential equation to have no solutions.

You might be interested in

Describe the transformation f(x) = 2x + 1 -> g(x) = -8(x + 4) - 1

katrin2010 [14]

f(x) = 2x + 1; Paren graph = x;

The graph was shifted one unit up and stretched 2 times.

g(x) = -8(x+4) - 1 = -8x - 32 - 1 = -8x - 33

The graph was shifted 33 units down and stretched 8 times and flipped 180 degrees.

8 0

3 years ago

Solve 32 x 74 = ? + 23 - 72

alekssr [168]

32 x 74 = 2368
23 - 72 = -49
2368 + 49 = 2417
2417 = ?

7 0

3 years ago

Read 2 more answers

According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e

slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that $p = 0.09$

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

$P(X < 4) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225$

$P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827$

$P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082$

$P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982$

Finally

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180$

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0

3 years ago

What is the midpoint between -2-3i and 3+9i

Svetlanka [38]

Answer:

1/2 + 3i is the midpoint between -2-3i and 3+9i.

Step-by-step explanation:

Given the complex number

-2-3i

3+9i

The formula to find the midpoint of two complex number (a + bi) and (c + di) is:

$M=\frac{\left(a+c\right)}{2}+\frac{\left(b+d\right)i}{2}$

$M=\frac{\left(-2+3\right)}{2}+\frac{\left(-3+\left(9\right)\right)i}{2}$

$M=\frac{-2+3+\left(-3+9\right)i}{2}$

$M=\frac{1+6i}{2}$

$M=\frac{1}{2}+3i$

Therefore, 1/2 + 3i is the midpoint between -2-3i and 3+9i.

3 0

3 years ago

Plz helpppp:Tammy conducted a survey to find the favorite subject of the students at her school. She asked 25 students from her

alexira [117]

Answer: Tammy's sample may not be vaild because she surveyed the students only from her class and it is likely that other classes might not like the subject maths. She might get the accurate results by surveying a larger number of people in the school instead of just her class.

3 0

3 years ago