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3 years ago

A locomotive (toy) travels at a velocity of 25 m/s for 10 s, then at 10 m/s for 5 minutes. What is the total distance covered?

Physics

1 answer:

Nadya [2.5K]3 years ago

8 0

The total distance covered by the locomotive (toy) during the first and second journey is 10500 meters.

D) The answer is not given in the Options.

<h3>What is the total distance covered?</h3>

Note that: Speed/velocity is distance traveled per unit time.

Speed = Distance ÷ time

Distance = velocity × time

Given that;

For the first journey,

velocity v = 25m/s
elapsed time t = 5min = (5×60)s = 300s

For the second journey,

velocity v = 10m/s
elapsed time t = 5min = (5×60)s = 300s

Distance covered in the first journey

Distance = velocity × time

Distance = 25m/s × 300s

Distance = 7500m

Distance covered in the second journey

Distance = velocity × time

Distance = 10m/s × 300s

Distance = 3000m

Total distance covered will be;

Total Distance = Distance covered in the first journey + Distance covered in the second journey

Total Distance = 7500m + 3000m

Total Distance = 10500m

Therefore, the total distance covered by the locomotive (toy) during the first and second journey is 10500 meters.

D) The answer is not given in the Options.

Learn more about speed here: brainly.com/question/7359669

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