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3 years ago

8

9.1÷3576 rounded to the nearest whole number

1 answer:

Mice21 [21]3 years ago

7 0

Answer:

Answer is 0

Step-by-step explanation:

$\frac{9.1}{3576}=0.0025447427$

Whole numbers are the set of numbers represented by {0,1,2,3.......}, So basically counting numbers with a 0. Whole numbers does not contain fractions or negative numbers.

Rounding off is a way of simplifying a number so that it is close to the value of the original number. 0.0025447427 lies in between the whole number 0 and 1. But is is a very small value and is close to 0 than 1. So the closet whole number is 0.

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Equation for the points (3,8) (2,6) on slope

Irina18 [472]

$\frac{8-6}{3-2} = \frac{2}{1}=4$

The slope is 2

y=2x + b

Plug in a point to solve for b
8 = 2(3) + b

8 = 6 + b
b = 2

The equation is y = 2x + 2

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3 years ago

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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

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Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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3 years ago

What else would need to be congruent to show that ABC =XYZ by SAS?<br> Given:<br> AB=XY<br> A=X

Sati [7]

ABC = XYZ by SAS

AB = XY - Side

A = X - Angle

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Removing the taken possible side, two sides can be congruent.

Either :

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Enter an equation for the function that includes the points.Give your answer in a(b)x. In the event that a=1 , give your answer

Andrews [41]

Answer:

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Step-by-step explanation:

Given

$(x_1,y_1) = (2,\frac{2}{3})$

$(x_2,y_2) = (3,\frac{5}{9})$

Required

Write the equation of the function $f(x) = ab^x$

Express the function as:

$y = ab^x$

In: $(x_1,y_1) = (2,\frac{2}{3})$

$y = ab^x$

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$y = ab^x$

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Divide (2) by (1)

$\frac{5}{9}/\frac{2}{3} = \frac{a*b^3}{a*b^2}$

$\frac{5}{9}/\frac{2}{3} = b$

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$a = \frac{2}{3} * \frac{36}{25}$

$a = \frac{2}{1} * \frac{12}{25}$

$a = \frac{24}{25}$

The function: $f(x) = ab^x$

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3 years ago

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ahrayia [7]

Answer:

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<em>hope this helps :)</em>

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