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1 year ago

Multiply 2/3 • 5/8 simplify your answer , if possible

Mathematics

1 answer:

Annette [7]1 year ago

6 0

Answer:

5/12

Step-by-step explanation: 2/3 x 5/8 Multiply the numerators ( top numbers) and the denominators ( bottom numbers ) 2x 5= 10 3x8=12 Simplify by 2 Answer=5/12

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Write an equation of the parabola in vertex form.

GenaCL600 [577]

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2 years ago

What is the value of x?

Evgesh-ka [11]

Answer:

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2 years ago

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The air pressure inside Jason’s bike tires decreases by about 6% each week. The original pressure was 45 pounds per square inch

Brrunno [24]

Compound percentage reduction can be calculated by multiplying the initial number by (1-x)^t where x is the percentage reduction (/100, i.e. 1% reduction is 0.01), and t is the number of times it has reduced.

So:
a) $p=45(1-0.06)^t=45*0.94^t$
Where t is the number of weeks.

We can then just substitute in to work out the final pressure:
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2 years ago

I do not know how to do this question?

alina1380 [7]

The probability he will select a hockey card is 1/4, and then the probability that he selects a baseball card without replacement is 1/6.

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2 years ago

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$