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KonstantinChe [14]
1 year ago
8

A construction company is analyzing which of its older projects need renovation. Building B was built two years before building

C. Building D was built two years before building B. The product of building B's age and building D's age is at least 195. If x represents the age of building C, which inequality represents this situation?
Mathematics
1 answer:
Black_prince [1.1K]1 year ago
3 0

The inequality x²+6x +8 ≥ 195 represents the provided situation option (D) x²+ 6x +8 ≥ 195 is correct.

<h3>What is inequality?</h3>

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have building B was built two years before building C.

The age of C is represented by x

Age of Building B:  

b = x + 2

Building D was built two years before building B

Age of Building d= x+4

The product of the building B’s age and building D’s age is at least 195.

b×d ≥ 195

(x+ 2)(x+4) ≥ 195

After solving we get:

x²+ 6x +8 ≥ 195

Thus, the inequality x²+6x +8 ≥ 195 represents the provided situation option (D) x²+ 6x +8 ≥ 195 is correct.

Learn more about the inequality here:

brainly.com/question/19491153

#SPJ1

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find the least perfect square that is exactly divisible by each of the numbers 5 , 18 , 25 and 27 . ​
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<h3>☂︎ Answer :- </h3>

  • 8100
<h3>☂︎ Solution :- </h3>

  • LCM of 5 , 18 , 25 and 27 = 2 × 3³ × 5²
  • 2 and 3 have odd powers . To get a perfect square, we need to make the powers of 2 and 3 even . The powers of 5 is already even .

In other words , the LCM of 5 , 18 , 25 and 27 can be made a perfect square if it is multiplied by 2 × 3 .

The least perfect square greater that the LCM ,

☞︎︎︎ 2 × 3³ × 5² × 2 × 3

☞︎︎︎ 2² × 3⁴ × 5²

☞︎︎︎ 4 × 81 × 85

☞︎︎︎ 100 × 81

☞︎︎︎ 8100

8100 is the least perfect square which is exactly divisible by each of the numbers 5 , 18 , 25 , 27 .

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70=x+16? Show how to do
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2 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

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Answer: the answer is B

Step-by-step explanation:

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