Answer:
55 Fahrenheit
Explanation:
Geothermal energy uses steam to produce electricity.
Superconducting materials don't generate anything.
But since their electrical resistance is zero, it's possible
to push a huge current through them without loss, and it's
the huge current that sets up a strong magnetic field around
the conductor.
Group 0 - they are called the NOBLE GASES
(as they're very unreactive) because...
ALL of their atoms are full.
Example : Helium contains 2 electrons so it's outer shell is full
Answer:
The overall velocity of the water when it hits the bottom is:
![v_f=63.61\ \frac{m}{s}](https://tex.z-dn.net/?f=v_f%3D63.61%5C%20%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
Use the law of conservation of energy.
Call it instant [1] to the moment when the water is just before reaching the falls.
At this moment its height h is 206 meters and its velocity horizontally
is
m/s.
At the instant [1] the water has gravitational power energy ![E_g](https://tex.z-dn.net/?f=E_g)
![E_g = mgh](https://tex.z-dn.net/?f=E_g%20%3D%20mgh)
The water also has kinetic energy Ek.
![E_k = 0.5mv_i ^ 2](https://tex.z-dn.net/?f=E_k%20%3D%200.5mv_i%20%5E%202)
Then the Total E1 energy is:
![E_1 = mgh + 0.5mv_i ^ 2](https://tex.z-dn.net/?f=E_1%20%3D%20mgh%20%2B%200.5mv_i%20%5E%202)
In the instant [2] the water is within an instant of touching the ground. At this point it only has kinetic energy, since the height h = 0. However at time [2] the water has maximum final velocity ![v_f](https://tex.z-dn.net/?f=v_f)
So:
![E_2 = 0.5mv_f ^ 2](https://tex.z-dn.net/?f=E_2%20%3D%200.5mv_f%20%5E%202)
As the energy is conserved then ![E_1 = E_2](https://tex.z-dn.net/?f=E_1%20%3D%20E_2)
![mgh + 0.5mv_i ^ 2 = 0.5mv_f ^ 2](https://tex.z-dn.net/?f=mgh%20%2B%200.5mv_i%20%5E%202%20%3D%200.5mv_f%20%5E%202)
Now we solve for
.
![gh + 0.5v_i ^ 2 = 0.5v_f ^ 2\\\\9.8(206) + 0.5(2.90) ^ 2 = 0.5v_f 2\\\\v_f^2 = \frac{9.8(206) + 0.5(2.90) ^ 2}{0.5}\\\\v_f = \sqrt{\frac{9.8(206) + 0.5(2.90) ^ 2}{0.5}}\\\\v_f=63.61\ \frac{m}{s}](https://tex.z-dn.net/?f=gh%20%2B%200.5v_i%20%5E%202%20%3D%200.5v_f%20%5E%202%5C%5C%5C%5C9.8%28206%29%20%2B%200.5%282.90%29%20%5E%202%20%3D%200.5v_f%202%5C%5C%5C%5Cv_f%5E2%20%3D%20%5Cfrac%7B9.8%28206%29%20%2B%200.5%282.90%29%20%5E%202%7D%7B0.5%7D%5C%5C%5C%5Cv_f%20%3D%20%5Csqrt%7B%5Cfrac%7B9.8%28206%29%20%2B%200.5%282.90%29%20%5E%202%7D%7B0.5%7D%7D%5C%5C%5C%5Cv_f%3D63.61%5C%20%5Cfrac%7Bm%7D%7Bs%7D)