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2 years ago

Find the magnitude of this vector:

Physics

1 answer:

xeze [42]2 years ago

3 0

Answer: = 25. 5 m

Explanation:

2-D vectors can be solved using the Pythagorean theorem:
$a^{2} +b^{2} =c^{2}$
The hypotenuse, or longest side is not given and that is what must be solved for
Direction can be omitted as the question only asks for magnitude
Magnitude: is the distance or quantity in which an object moves during motion

Solve for C using Pythagorean theorem:

1. $\sqrt{a^{2}+b^{2} }=c$

2. $\sqrt{22.2 m ^{2} +12.6m^{2} } =c$

3. $25.52646 m= c$

round to lowest number of significant digits when dividing and multiplying
rounded to 3 significant digits

∴ Magnitude of the vector is 25.5 m

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There are four charges, each with a magnitude of 2.06 µC. Two are positive and two are negative. The charges are fixed to the co

mars1129 [50]

Answer:

0.208 N

Explanation:

We are given that

$q_1=q_2=2.06\mu C=2.06\times 10^{-6} C$

$q_3=q_4=-2.06\mu C=-2.06\times 10^{-6} C$

Distance,d=0.41 m

The magnitude of the net electrostatic force experienced by any charge at point 4

Net force, $F_{net}=\sqrt{F^2_1+F^2_3+2F_1F_3cos90^{\circ}}-F_2$

$F_1=F_3=F$

$F_{net}=\sqrt{F^2+F^2+0}-F_2$

$F_{net}=\sqrt 2F-F_2$

$F=\frac{kq^2}{d^2}$

$F_2=\frac{Kq^2}{2d^2}$

$F_{net}=\frac{\sqrt 2kq^2}{d^2}-\frac{kq^2}{2d^2}=\frac{kq^2}{d^2}(\sqrt 2-\frac{1}{2})$

Where $k=9\times 10^9$

$F_{net}=\frac{9\times 10^9\times (2.06\times 10^{-6})^2}{(0.41)^2}(\sqrt 2-\frac{1}{2})$

$F_{net}=0.208 N$

3 0

3 years ago

Is density the degree of compactness of a substance?

san4es73 [151]

Yes it is, in other simplified terms density compares the amount of matter an object has to its volume.

5 0

4 years ago

A transverse wave has a frequency of 200 Hz with a wavelength of 1.0 m. Determine the speed

Lana71 [14]

Answer:

200 m\ s Ans .....

Explanation:

Data:

f = 200 Hz

w = 1.0 m

v = ?

Formula:

v = f w

Solution:

v = ( 200)(1.0)

v = 200 m\s Ans .........

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3 years ago

a bus moving at speed of 25m/s beginning to slow at rate 4m/s^2each second how long does it take to stop

Paladinen [302]

Explanation:

Initial velocity is 25m/s i.e. u. Final velocity would be zero since the bus stopped. It is noted that the bus deccelartion of 4m/s, so the acceleration should be considered negative of 4m/s I.e. 4m/s. So using third law of motion i.e.

v^2 - u^2= 2as

(0)^2 - (25)^2= -2×4×s {Note here I used minus sign in acceleration}

-625 = -8×s

s=625 ÷ 8

s= 125 m

So bus would cover a distance of 125m before coming to rest.

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3 years ago

I need the answer for Earths mass and the mass and weight for Mars.

Savatey [412]

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8 0

3 years ago