Solve the following questions-

Mathematics

1 answer:

Setler79 [48]2 years ago

3 0

Answer:

2/5

Step-by-step explanation:

To get the ratio as a pure number, it must be expressed as the quotient of two values that have the same units. For the purpose here, it is convenient to convert both values to units of seconds.

<h3>units conversion</h3>

The conversion factor between minutes and seconds is ...

1 minute = 60 seconds

Multiplying this equation by 3 gives ...

3 minutes = 180 seconds

<h3>ratio of interest</h3>

Then the desired ratio is ...

(72 seconds)/(3 minutes) = (72 seconds)/(180 seconds) = 72/180

= (36×2)/(36×5)

= 2/5

The ratio in its simplest form is 2/5.

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ABC is translated 6 units up and 3 units left to create ∆A'B'C'.

aivan3 [116]

B is the right answer for this

6 0

3 years ago

Janice is 7 years older than Tam. Complete the table, and then graph this situation.

qwelly [4]

Answer:

The table in the exercise can be completed with the next results:

x y
2 9
4 11
6 13
8 15

Step-by-step explanation:

As in the exercise Janice is 7 years older than Tam, to obtain the result in the table, you must add 7 to each age in the column x, with this we can make the next formula:

y = x + 7

Remember that x is Tam's age, and y is Janice's age, so, you must replace the x variable in each case to obtain the result to y:

When x is 2:

y = 2 + 7
y = 9

When x is 4:

y = 4 + 7
y = 11

When x is 6:

y = 6 + 7
y = 13

When x is 8:

y = 8 + 7
y = 15

At last, to obtain the graph you can use the formula made: y = x + 7, and you'll obtain a graph like the attached picture, where each time x obtain a unit, the y variable obtain a unit too maintaining the diference of 7.

8 0

2 years ago

In the triangle shown we can find the angle θ as follows calculator

Xelga [282]

Given a right triangle with hypothenus of measure 34, the side opposite the angle θ of measure 30, and the side adjacent the angle theta of measure 16.

$\sin\theta= \frac{opposite}{hypothenuse} = \frac{30}{34} = \frac{15}{17} \\ \\ \Rightarrow \theta=\sin^{-1}\left( \frac{15}{17} \right) \\ \\ \\ \cos\theta= \frac{adjacent}{hypothenuse} = \frac{16}{34} = \frac{8}{17} \\ \\ \Rightarrow \theta=\cos^{-1}\left( \frac{8}{17} \right) \\ \\ \\ \tan\theta= \frac{opposite}{adjacent} = \frac{30}{16} = \frac{15}{8} \\ \\ \Rightarrow \theta=\cos^{-1}\left( \frac{15}{8} \right)$