The big advantage to using continuous compounding to express growth rates is it avoids the problem of asymmetry in growth rates:
For example, if we use the normal definition and $100 grows to $105 in one time period, that's a growth rate of $105/$100 - 1 = 5% But if $105 decreases to $100, that's a growth rate of $100/$105 - 1 = -4.76%
The problem of asymmetry is those two growth rates, 5% and -4.75% are not equal up to a sign.
But if you use continuous compounding the growth rate in the first case is ln(105/100) = 0.04879.
And the growth rate in the second is ln (100/105) = -0.04879.
Those two growth rates are definitely the negative of each other.<span>
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Answer:
Explanation:
2K + Cl₂ ⟶ 2KCl
n/mol: 2.00
2 mol of KCl are formed from 2 mol of K
Hello!
The reaction that took place was
B) exothermic. The equation for the ΔH is
To know if this reaction is
exothermic or
endothermic we will need to look at the
sign of the
ΔH. If it is
positive, it means that enthalpy of the products is
higher than the enthalpy of the reagents and the reaction is
endothermic.
If the sign is negative, it means that the enthalpy of the products is
lower than the enthalpy of the reagents and the reaction is
exothermic. In this case, the sign is negative, so the reaction is exothermic.
Have a nice day!
Answer:
The rate of the catalyzed reaction will increase by a 1.8 × 10⁵ factor.
Explanation:
The rate of a reaction (r) is proportional to the rate constant (k). We can find the rate constant using the Arrhenius equation.
where,
A: collision factor
Ea: activation energy
R: ideal gas constant
T: absolute temperature (125°C + 273 = 398 K)
For the uncatalized reaction,
For the catalized reaction,
The ratio kC to kU is 6.0 × 10⁻⁸A/3.4 × 10⁻¹³A = 1.8 × 10⁵
Answer:
Displacement is the direction from the starting point and the length of a directly line from the starting point to the ending point.