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2 years ago

Question number 1 please help The decimal one

Mathematics

1 answer:

allochka39001 [22]2 years ago

6 0

The average of any two numbers always falls between those two numbers.

So one number between 0.65340 and 0.65345 could be

(0.65340 + 0.65345)/2 = 1.30685/2 = 0.653425

You can also compare the first several digits of the two numbers:

0.65340

0.65345

They both have the same digits up to the 5th digit after the decimal point. So you can get any number between them by incrementing (increasing by 1) the last digit to get e.g. 0.65341, or tack on any number of more digits to get a number larger than 0.65340, like 0.635401 or 0.63540000123, etc.

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A bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y = ________.A.

LUCKY_DIMON [66]

Answer:

D. $\frac{4}{3}$

Step-by-step explanation:

We have been given that a bag contains x blue chips and y red chips. The probability of selecting a red chip at random is 3/7. We are asked to find the $\frac{x}{y}$ .

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

$P(\text{Red})=\frac{\text{Number of red chips}}{\text{Total number of chips}}$

$P(\text{Red})=\frac{y}{x+y}$

Since we are told that probability of selecting a red chip at random is 3/7, so red balls are 3 and total balls are 7:

$P(\text{Red})=\frac{3}{x+3}$

Since total balls are 7, so we will get:

$x+3=7\\x=4$

Upon substituting $x=4\text{ and } y=3$ in expression $\frac{x}{y}$ , we will get:

$\frac{4}{3}$

Therefore, the value of $\frac{x}{y}$ is $\frac{4}{3}$ and option D is the correct choice.

7 0

3 years ago

CAN SOMEONE HELP ME PLSS IM FAILING AND I RLLY NEED HELP HELP ASAP HELP MATH MATH MATH HELPPPPPPPPPP

Leno4ka [110]

Answer:

Hello if I know the answers to your math questions I'll answer if there already posted I'll check your profile if not please post them thank you!

4 0

3 years ago

A concrete patio is

astra-53 [7]

The length of concrete patio is 6.5 feet which is less than given 7 foot picnic table. So the concrete slab is not enough to fit a 7 foot picnic table

Solution:

Given that concrete patio is $5\frac{2}{3}$ feet wide

Area of concrete patio = $36\frac{2}{3}$ square feet

Therefore,

$\texttt{Width of concrete patio = }5\frac{2}{3}=\frac{5\times 3+2}{3}=\frac{17}{3}feet\\\\\text{Area of concrete patio = }36\frac{2}{3}=\frac{36\times 3+2}{3}=\frac{110}{3}feet^2$