Mar 12, 8:09:33 PM

A new club sent out 172 coupons to boost sales for next year's memberships. They provided 3 times as many to potential members

cricket20 [7]

Answer: 172: 4= 43

43× 3= 129

172-129= 43

Odp.Wysłali 43 kupony do istniejących członków.

Step-by-step explanation:1.bo wysłali 3×wiecej i jeszcze są istniejący członkowie

2.ile wyslali potencialnym

3.i ile wyslali do istniejacych

4 0

3 years ago

Two trucks leave a warehouse at the same time. one travels due west at an average speed of 49 miles per hour, and the other trav

Gre4nikov [31]

Well there can be two different solutions for this but i will choose the easier one. Obviously one requires a system of equations which obviously will involve a lot of thinking and some good algebra solving in order for them to solve.

So we can just keep adding the distance as we know they are in different directions. 49 + 65 = 114. So 114 * 4.5 = 513 miles. SO after around 4.5 hours they will be 513 miles apart.

4 0

3 years ago

Brenna owns 9 T-shirts, 3 of which are red.

Ulleksa [173]

Answer:

1/3

Step-by-step explanation:

9 Shirts, 3 are Red

Probability: 3/9

Simplify: 1/3

5 0

3 years ago

A manager is comparing wait times for customers in a coffee shop based on which employee is

anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

$H_0: \mu_A - \mu_B = 0$

At the alternative hypothesis, it is tested if there is difference, that is:

$H_1: \mu_A - \mu_B = 0$

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

$\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2$

$\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4$

For the distribution of differences, we have that:

$\overline{x} = \mu_A - \mu_B = 73 - 74 = -1$

$s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447$

<h3>What is the test statistic?</h3>

It is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{-1 - 0}{0.447}$

$t = -2.24$

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0

2 years ago

HELP PLEASEE!!! I just need help with the 2 boxes

Soloha48 [4]

Answer:

$y= x - 300$