
has to be differentiable on [-1, 1] for the theorem to hold. This is not the case because the derivative doesn't exist at

.


but clearly

is undefined.
Answer:
x = -1 + 5y
Step-by-step explanation:
If you writing this equation in terms of x then the answer is correct, however, if there is a value for y, then you just need to sub it into y.
For example,
Find x when y = 3
x = -1 + 5(3)
= -1 + 15
= 14
Answer:
The longest bar in her histogram is the Intervals 5-9 with the value of 5
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo
My answer:
- Intervals 0-4 : there are 2 results
- Intervals 5-9 : there are 5 results
- Intervals 10-14 : there are 4 results
- Intervals 15-19 : there are 5 results
So the longest bar in her histogram is the Intervals 5-9 with the value of 5
Hope it will find you well.
Finding the x-intercept first:
5 (x - 2) = y - 3
5x - 10 = 0 - 3
5x - 10 = -3
5x = 7
x = 7/5 or 1.4
Solve for y
y - 3 = 5 (0 - 2)
y - 3 = 0 - 10
y - 3 = -10
y = - 7
Answer:
asnwer 24
Step-by-step explanation:
x = 3
y = 1/3
z = 5
------------------------------
5( 3 ) - 3(1/3) + 2(5)
15 - 1 + 10 = 24