ITS TOO SMALL TO SEE THAT PRINT, BUT CAN SOMEONE PLEASE HELP ME ANSWER THIS PROBLEM ON MY PROFILE I JUST POSTED IT AND NO ONE WILL HELP ME!!1
Answer:
Step-by-step explanation:
Remark
Anything multiplied by 0 = 0. So the whole right side is 0.
(6x - 9)*3 - 1 = 0 Add 1 to both sides.
(6x - 9)*3 - 1 + 1 = 0 + 1 Combine
(6x - 9)*3 = 1 Divide both sides by 3
(6x - 9)*3/3 = 1/3 Simplify
(6x - 9) = 1/3 Remove brackets. Add 9 to both sides
6x - 9+9 = 9 1/3 Combine
6x = 9 1/3
6x = 28/3 Divide both sides by 6
6x / 6 = 28/3 // 6 Invert the 6 and multiply.
x = 28/3 * 1/6
x = 28/18
Answer
x = 14/9
Answer:
c brainliest please
Step-by-step explanation:
Answer and Step-by-step explanation:
(a) Given that x and y is even, we want to prove that xy is also even.
For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.
(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:
Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.
(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.
Answer:
So basically anything higher than .5 would be x>.5 so it has to be greater than or equal to .51
Step-by-step explanation:
.51 .75 .89 .56 .78 .86 .61 it goes on and on as long as it is greater than .50
