Answer:
x = -6/5
y =7/5
Step-by-step explanation:
2x + y = - 1
x - 2y = - 4
Multiply the first equation by 2 so we can eliminate y
2(2x + y = - 1)
4x + 2y = -2
Add this to the second equation
4x + 2y = -2
x - 2y = - 4
---------------------
5x + 0y = -6
Divide by 5
5x/5 = -6/5
x = -6/5
Multiply the second equation by -2 so we can eliminate x
-2(x - 2y = - 4)
-2x+4y = 8
Add this to the first equation
2x + y = - 1
-2x+4y = 8
---------------------
0x + 5y = 7
Divide by 5
5y/5 = 7/5
y =7/5
Answer:
m`1 = 43` 2,3
m<2 1/12*
and m <3 = 1,3/2
Step-by-step explanation:
Answer:
ummmmm..... ykw I cant do that but I will give out free brainly points sooo ya (on a question)
Step-by-step explanation:
Joint Frequency because of the fact that it "joins" one number from the column(up and down) and one from the row(side-by-side), hence the two-way table.
Both the general shape of a polynomial and its end behavior are heavily influenced by the term with the largest exponent. The most complex behavior will be near the origin, as all terms impact this behavior, but as the graph extends farther into positive and/or negative infinity, the behavior is almost totally defined by the first term. When sketching the general shape of a function, the most accurate method (if you cannot use a calculator) is to solve for some representative points (find y at x= 0, 1, 2, 5, 10, 20). If you connect the points with a smooth curve, you can make projections about where the graph is headed at either end.
End behavior is given by:
1. x^4. Terms with even exponents have endpoints at positive y ∞ for positive and negative x infinity.
2. -2x^2. The negative sign simply reflects x^2 over the x-axis, so the end behavior extends to negative y ∞ for positive and negative x ∞. The scalar, 2, does not impact this.
3. -x^5. Terms with odd exponents have endpoints in opposite directions, i.e. positive y ∞ for positive x ∞ and negative y ∞ for negative x ∞. Because of the negative sign, this specific graph is flipped over the x-axis and results in flipped directions for endpoints.
4. -x^2. Again, this would originally have both endpoints at positive y ∞ for positive and negative x ∞, but because of the negative sign, it is flipped to point towards negative y ∞.
