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3 years ago

|1| Identify the property shown.

Mathematics

1 answer:

Vitek1552 [10]3 years ago

7 0

Answer: The answer is B associative

Step-by-step explanation:

Because both of the variables associate each other .

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One the first problem on finding the constant of <span> proportionality in this situation the answer is 2. Below is the solution:

constant = unit rate
unit rate = $2/ poung
K = 2

For the second question, the equation is the below:

T = 2p or y = 2x</span>

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A football coach gives half his players a protein bar to eat before each game; the other players do not receive the protein bar.

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To make the sure the results did not happen by chance, the coach can ensure that the protein bars are the only difference between the two groups. For example, he can make sure that both groups are drinking the same amounts of water and getting in the same amount of practice; that way, he will be able to determine that one group is performing better due to the protein bars only. Also, the coach can repeat this experiment multiple times to make sure that the results weren't a random, one-time thing.

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3 years ago

15 = 3n + бр.<br> help!

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3 years ago

A poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ag

Katyanochek1 [597]

Answer:

At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll

Step-by-step explanation:

Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.

Let five years ago be group I X and as of now be group II Y

$H_0: p_x =p_y\\H_a: p_x \neq p_y$

(Two tailed test at 5% level of significance)

Group I Group II combined p

n 270 300 570

favor 120 140 260

p 0.4444 0.4667 0.4561

Std error for differene = $\sqrt{\frac{0.4561(1-0.4561)}{570} } \\=0.0209$

p difference = -0.0223

Z statistic = p diff/std error = -1.066

p value =0.2864

Since p value >0.05, we accept null hypothesis.

At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll

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3 years ago